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Test:	Quiz 05
Number of Questions:	5
Time:

$\displaystyle \int_{0}^{1}\left(x^{2}+\sqrt{x}\right)dx$

	$2$
	$1/2$
	$3$
	$3/2$
	$1$

$\displaystyle \int\sin 3x\ dx$

	$\sin 3x+C$
	$-\sin 3x+C$
	$-\frac{1}{3}\sin 3x+C$
	$-\frac{1}{3}\cos 3x+C$
	$\cos 3x+C$

$\displaystyle \int\frac{3}{\left(2-x\right)^{2}}\ dx$

	$\frac{3}{(2-x)^2}+C$
	$3(2-x)^2+C$
	$3\ln(2-x)^2+C$
	$3(2-x)+C$
	$\frac{3}{2-x}+C$

$\displaystyle \int\left(\theta^{4}-2\theta^{2}+8\theta-2\right)\left(\theta^{3}-\theta+2\right)d\theta$

	$\left(\theta^{4}-2\theta^{2}+8\theta-2\right)^{2}+C$
	$\frac{\left(\theta^{4}-2\theta^{2}+8\theta-2\right)^{2}}{8}+C$
	$\frac{\left(\theta^{4}-2\theta^{2}+8\theta-2\right)^{2}}{6}+C$
	$\frac{\left(\theta^{4}-2\theta^{2}+8\theta-2\right)^{2}}{4}+C$
	$\frac{\left(\theta^{4}-2\theta^{2}+8\theta-2\right)^{2}}{2}+C$

$\int x^{3}\ln xdx$

	$\frac{1}{16}x^{4}\ln x+\frac{1}{4}x^{4}+C$
	$\frac{1}{16}x^{4}\ln x-\frac{1}{4}x^{4}+C$
	$-\frac{1}{16}x^{4}\ln x-\frac{1}{4}x^{4}+C$
	$-\frac{1}{16}x^{4}\ln x+\frac{1}{4}x^{4}+C$
	$\frac{1}{4}x^{4}\ln x-\frac{1}{16}x^{4}+C$

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