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%%%%%%%%%%%%%%%%%%%%%%%%% A NOTE ON ESSENTIAL DUALITY %%%%%%%%%%%%%%%%%%%%%%
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%  BY JAKOB YNGVASON %%%%%%%%%%%%%%%%%%%%%%%%%%%%
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\tabsatz
\centerline{\hbf A Note on Essential Duality}
\vskip 0.4cm
\centerline{\caps Jakob Yngvason}
\mabsatz
\centerline{Science Institute}
\centerline{University of Iceland}
\centerline{Dunhaga 3, IS 107 Reykjavik, Iceland}
\babsatz
\babsatz \centerline {\bf ABSTRACT} \bigskip 
By considering some simple models it is shown that the essential duality 
condition for local nets of von Neumann algebras associated with Wightman 
fields need not be fulfilled if Lorentz covariance is dropped. These models 
illustrate a point made by Borchers in the proof of his two dimensional CPT 
theorem for local nets: The Lorentz covariant net constructed from the 
wedge algebras of a given two dimensional net may not be unique. It is also 
shown that in higher dimensions the Lorentz boosts constructed by means of 
the modular groups of wedge algebras may act nonlocally in the directions 
parallel to the edge of the wedge. 



\babsatz\vfill\eject
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
\noindent{\bbf 1. Introduction}
\bigskip

One of the most remarkable results in algebraic quantum field theory in 
recent years is Borchers' derivation of the CPT theorem for local nets in 
two dimensional space-time [B]. The main ingredient in this proof is a 
certain converse of the Bisognano-Wichmann analysis of modular structures 
in quantum field theory [BW1,2], (see also [BY]): Whereas Bisognano and 
Wichmann assume covariance with respect to Lorentz transformations and show 
that the Lorentz boosts coincide with the modular group of the algebra 
corresponding to a wedge-domain, Borchers proves that in two dimensions the 
modular group of a wedge algebra can be used to define a representation af 
the Poincar\'e group, if the net is covariant with respect to a 
representation of the translation group satisfying the spectrum condition. 
Moreover, the initial net can be embedded into a net that is covariant with 
respect to this representation af the Poincar\'e group, has CPT symmetry 
and satisfies Haag-duality. 


As pointed out in [B], the Poincar\'e covariant net obtained by this method 
may not be unique unless the initial net satisfies wedge duality [BW1,2]. 
This condition of wedge duality is also important in another context: It 
implies essential duality [Ro], which is one of the chief assummptions on 
which the analysis of superselection rules is based [H]. By the results of 
Bisognano and Wichmann wedge duality always holds for local nets generated 
by Wightman fields transforming with respect to finite dimensional 
representations of the Lorentz group, but examples of local nets violating 
this condition have apparently not been known so far. 


In the present note we     
discuss a class of very simple fields in two dimensions, whose duality 
properties can be completely analyzed. Among these fields are both such 
that violate essential duality (and hence, {\it a fortiori} wedge 
duality), as well as fields that
satisfy wedge duality without being Lorentz covariant. The former provide 
examples where the net has infinitely many different extensions 
satisfying duality. Higher dimensional 
fields of a similar type 
demonstrate clearly
that some additional assumptions are needed to 
extend Borchers' result to space-time dimensions larger 
than 2, because the action of the
modular group of a wedge algebra in directions parallel to the 
edge of the wedge is not local in these examples. 
%It seems advisable to keep these 
%examples in mind in
%the search for a general CPT theorem within the framework of local 
%observables.
\vfill\eject
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
\noindent{\bbf 2. Generalized free fields on a light ray}
\bigskip
Let $(x^0,x^1)$ denote the usual time and space coordinates in two 
dimensional Minkowski space and $x_\pm=x^0\pm x^1$ the corresponding light 
cone coordinates. Suppose $\Phi$ is a hermitian Wightman field that 
transforms covariantly under space-time translations, but not necessarily 
under Lorentz transformations, and depends only on one light cone 
coordinate, say $x_+$. Locality implies that the commutator 
$[\Phi(x_+),\Phi(y_+)]$ has support only for $x_+=y_+$. Moreover, from the 
spectrum condition it follows that the generator for translations of 
$\Phi$ in the $x_+$-direction, $P^0-P^1$, is positive semidefinite. 
This implies readily that the Fourier transform of the two point function, 
${\cal W}_2$, defined by $\la\Omega, 
\Phi(x_+)\Phi(y_+)\Omega\ra=(1/2\pi)\int \exp[ip(x_+-y_+)]\tilde {\cal 
W}_2(p) dp$, with $\Omega$ the vacuum vector, has the form $$\tilde {\cal 
W}_2(p)=\theta(p) p Q(p^2)+c\delta(p),\eqno(2.1)$$ where $Q(p^2)$ is a 
positive, even polynomial in $p\in\BR$, $\theta(s)=1$ for $s\geq 0$ and 
zero else, and $c=\la\Omega,\Phi(x_+)\Omega\ra^2\geq 0$ is a constant. 
Subtracting $c^{1/2}$ from $\Phi$ if necessary, we may drop the 
$\delta(p)$-term. For simplicity of notation we also from now on write 
$x,y$ instead of $x_+,y_+$.


The models we consider are generalized free fields with the two point 
function (2.1) (without the $\delta$-term). They are characterized by the 
commutation relations $$[\Phi(x),\Phi(y)]=DQ(D^2)\delta(x-y){\bf 
1},\eqno(2.2)$$ where we have for convenience denoted $id/dx$ by $D$. The 
simplest case is the chiral $U(1)$-current $\Phi_0$, given by 
$$[\Phi_0(x),\Phi_0(y)]=D\delta(x-y){\bf 1}.\eqno(2.3)$$ The other models 
can be obtained from $\Phi_0$ by differentiation. To see 
this, one notes that since $Q(p^2)$ is positive and an even function of 
$p$, one can 
write 
$$Q(p^2)=L(p)L(-p),\eqno(2.4)$$
 where $L(p)$ is a polynomial satisfying 
$$L(-p)=L(p)^*.\eqno(2.5)$$ 
The polynomial $L(p)$ is uniquely fixed (up to a sign) for a given $Q(p^2)$ 
by the requirement 
that its zeros lie in the closed upper half plane. The most 
general form of $L(p)$ is then
$$L(p)=R(p)P(p),\eqno(2.6)$$
where $R(p)$ has zeros  only on the real axis and can be written as
$$R(p)=(ip)^n \prod_{j=1}^{k}(p^2-r_j^2),\eqno(2.7)$$
with $r_j>0$, while $P(p)$ is a polynomial whose zeros have a strictly 
positive imaginary part. Note that $P(p)$ satisfies the 
reality condition (2.5) and $R(-p)=(-1)^nR(p)$. From (2.4) and (2.5) it is 
clear that the field 
$\Phi$ defined by
$$\Phi(x)=L(D)\Phi_0(x)\eqno(2.8)$$
satisfies the commutation relation (2.2). It also follows that the smeared 
field operators $\Phi(f)$ are well defined and essentially self adjoint 
on their natural domain for every tempered real distribution $f$ 
such that $L(p)\tilde{f}(p)$ is square integrable with respect to the 
measure $\vert p\vert dp$. Such $f$ are necessarily measurable functions, 
but they may have singularities and grow at infinity if $L(p)$ has zeros 
on the real axis. 

Since on a light ray Lorentz boosts are the same as dilatations, the field 
$\Phi$ is Lorentz covariant if and only if $Q(p^2)=p^{2n}$ for some natural 
number $n$, i.e. $$\Phi(x)=(d/dx)^n\Phi_0(x).\eqno(2.9)$$ In fact, if 
$U_0(\lambda)$ is the unitary operator implementing dilatation by 
$\lambda>0$ for $\Phi_0$, i.e.,\ 
$U_0(\lambda)\Phi_0(x)U_0(\lambda)^{-1}=\lambda\Phi_0(\lambda x)$, then 
$$U_0(\lambda)\Phi(x)U_0(\lambda)^{-1}=\lambda^{n+1}\Phi(\lambda 
x)\eqno(2.10)$$ for $\Phi$ as in (2.9).


The two point function for the field (2.9) is $${\cal W}_2(x-y)=(2\pi)^{-1} 
(x-y+i0)^{-2(n+1)}.\eqno( 2.11)$$ A M\"obius transformation, $x\mapsto 
x^\prime={ax+b\over cx+d}$ with $a,b,c,d\in\BR$ and $ad-bc>0$, changes 
${\cal W}_2$ according to the formula $${\cal 
W}_2(x^\prime-y^\prime)dx^\prime dy^\prime= \left[{(cx+d)(cy+d)\over 
ad-bc}\right]^{2n} {\cal W}_2(x-y)dx dy.\eqno(2.12)$$ It follows that there 
is a unitary representation of the M\"obius group implementing the 
transformations $\Phi(f)\mapsto\Phi(f^\prime)$ with 
$$f^\prime(x^\prime)={(ad-bc)^n\over 
(cx+d)^{2n}}f(x)={(cx^\prime-a)^{2n}\over 
(ad-bc)^n}f(-(dx^\prime-b)/(cx^\prime-a)).\eqno(2.13)$$ As a consequence 
the field (2.9) can be extended to a conformally covariant field on the 
compactified light ray [BSch]. 


Returning to the general case (2.8) we define the unitary Weyl operators as
usual by
$$W(f)=e^{i\Phi(f)},\eqno(2.14)$$
where $f$ is a real function such that $L(p)\tilde{f}(p)$ is square 
integrable with respect to the 
measure $\vert p\vert dp$. The Weyl relations are
$$W(f)W(g)=e^{-K(f,g)/2} W(f+g)\eqno(2.15)$$
with
$$K(f,g)=\la\Omega,[\Phi(f),\Phi(g)]\Omega\ra=
\int_{-\infty}^{\infty}p\, Q(p^2)\tilde{f}(-p) 
\tilde{g}(p) dp.\eqno(2.16)$$
It follows that $W(f)$ commutes with $W(g)$ if and only if $K(f,g)=0$, in 
particular if $f$ and $g$ have disjoint 
supports.

Using the concrete realization of $\Phi$ as a derivative of $\Phi_0$ we 
can write
$$W(f)=W_0(L(D)f)\eqno(2.17)$$
with $W_0(g)=\exp(i\Phi_0(g))$, and
$$K(f,g)=K_0(L(D)f,L(D)g)=K_0(Q(D^2)f,g)=K_0(f,Q(D^2)g)\eqno(2.18)$$
where $K_0$ is the vaccum expectation value of the commutator for $\Phi_0$.
We note also that the Weyl operators are weakly continuous in 
$f$ with respect to the norm 
defined by the two point function, {\it viz},
$$\Vert \tilde{f}\Vert^2=\int_0^\infty p \vert L(p)\tilde{f}(p)\vert^2 
dp.\eqno(2.19)$$


The Weyl operators generate on Fock space a local net of von Neumann 
algebras ${\cal M}(I)=\{W(f)\mid {\rm supp\ }f\subset I\}^{\prime\prime}$ 
associated with bounded intervals $I$ of the light ray $\BR$. 
Alternatively, one may think of these algebras as a net over 
two-dimensional Minkowski space. If $ {K}$ is an open double cone on 
Minkowski space we define ${\cal A}(K)={\cal M}(I)$, where $I$ is the 
projection of $K$ onto the light ray $x_-=0$. Locality of the net ${\cal 
M}(\cdot)$ for disjoint intervals is equivalent to the locality of ${\cal 
A}({\cdot})$ for space like separated double cones. 


Duality conditions for the net ${\cal A}({\cdot})$ also translate 
immediately into corresponding conditions for ${\cal M}(\cdot)$. {\it 
Duality} for double cones, i.e., the condition ${\cal A}(K)^\prime={\cal 
A}(K^\prime)$ for all doble cones $K$, is equivalent to ${\cal 
M}(I)^\prime={\cal M}(I^\prime)$ for all intervals $I$. Here $K^\prime$ 
denotes as usual the space like complement of the closure of $K$, whereas 
$I^\prime$ denotes the set theoretical complement of the closure of $I$ in 
$\BR$. The algebras corresponding to unbounded subsets of $\BR^2$ or $\BR$ 
are by definition generated by the subalgebras corresponding to double 
cones or intervals, repectively, contained in the unbounded sets. {\it 
Essential duality} for ${\cal A}(\cdot)$ means that the net $K\mapsto{\cal 
A}(K^\prime)^\prime$ satisfies locality; this is equivalent to 
$I\mapsto{\cal M}(I^\prime)^\prime$ being local. Finally, {\it wedge 
duality}, which implies essential duality [BW1,2] (see also [BY]), is the 
condition ${\cal A}(W)^\prime={\cal A}(W^\prime)$ for all space like wedges 
$W$. This is equivalent to ${\cal M}(\BR^+)^\prime={\cal M}(\BR^-)$, where 
$\BR^{\pm}$ denotes the positive or negative half axis. 

% 
\bigskip
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%% 
\noindent
{\bbf 3. The Algebras ${\cal M}(I)$, ${\cal M}(I^\prime)$ and ${\cal 
M}(\BR^\pm)$} \bigskip 
The net ${\cal M}(\cdot)$ generated 
by $\Phi=L(D)\Phi_0$ may be regarded as a subnet of the net 
${\cal M}_0(\cdot)$ generated by the 
chiral $U(1)$-current $\Phi_0$. One may ask to what extent the algebras 
${\cal M}(I)$, ${\cal M}(I^\prime)$ and ${\cal 
M}(\BR^\pm)$ 
depend on the polynomial $L(p)$, in particular when they are equal to the 
corresponding algebras generated by $\Phi_0$.
The answer given below can be summarized as follows: If $I$ is a bounded 
interval, then  polynomials differing by more than a constant factor 
lead to different ${\cal 
M}(I)$, while
${\cal M}(I^\prime)$ depends only on the roots of $L(p)$ in the open 
upper half plane,
and the same holds for ${\cal 
M}(\BR^\pm)$.   
   
To discuss this in more detail let ${\cal M}_1(\cdot)$ and ${\cal M}_2 
(\cdot)$ denote two such nets corresponding to different polynomials 
$L_1(p)$ and $L_2(p)$. It is clear that if $L_1(p)$ is a factor of 
$L_2(p)$, then ${\cal M}_2(\cdot)$ is a subnet of ${\cal M}_1(\cdot)$. We 
now show that conversely, if $L_1(p)$ is not a factor of $L_2(p)$, then 
${\cal M}_2(I)$ is not a subalgebra of ${\cal M}_1(I)$ for a bounded 
interval $I$. In particular, ${\cal M}_1(I)\neq{\cal M}_2(I)$, unless $L_1$ 
and $L_2$ are proportional to each other. 


To see this, note that if $L_1$ is not a factor of $L_2$, then one 
can find a real test function $g$ such that $DL_1(-D)L_2(D)g(x)=0$ on $I$, 
while $DL_2(-D)L_2(D)g$ is nonzero on some open 
subinterval of $I$. (Recall that $L_1$ and $L_2$ satisfy the reality 
condition (2.5).) By the first property it is clear that 
$W_2(g)=W_0(L_2(D)g)$ commutes with all $W_1(f)=W_0(L_1(D)f)$ with ${\rm 
supp }f\subset I$, so $W_2(g)\in {\cal M}_1(I)^\prime$. On the other hand, if 
$DL_2(-D)L_2(D)g$ is nonzero on 
a subinterval of $I$ then one has for some $f$ with support in $I$ that 
$$K_0(L_2(D)f,L_2(D)g)=\int f(x)DL_2(-D)L_2(D)g(x)dx\neq 0,\eqno(3.1)$$
and thus $W_2(g)\notin {\cal M}_2(I)^\prime$. Hence ${\cal 
M}_1(I)^\prime\not\subset{\cal M}_2(I)^\prime$.

By an analogous argument, with $I$ replaced by $I^\prime$ or $\BR^\pm$, one 
sees that ${\cal M}_2(I^\prime)\not\subset{\cal M}_1(I^\prime)$ 
and ${\cal M}_2(\BR^\pm)\not\subset{\cal M}_1(\BR^\pm)$ if the 
polynomial $P_1(p)$, obtained by cancelling the real zeros of $L_1(p)$,
is not a 
factor of the corresponding polynomial $P_2(p)$ for 
$L_2(p)$. For instance, suppose $P_1(\alpha)=0$ while $P_2(\alpha)\neq 
0$, for some $\alpha$ in the open upper half plane. The test function 
$g(x)=h(x)\exp(i\alpha x)$, where $h$ is a $C^\infty$-function with 
$h(x)=1$ on 
$\BR^+$, satisfies the equation $DL_1(-D)L_2(D)g=0$ on $\BR^+$, but 
$DL_2(-D)L_2(D)g$ is nonzero on some interval in $\BR^+$. As above, we 
conclude from this that $W_2(g)\in\CM_1(\BR^+)^\prime$ and 
$W_2(g)\not\in\CM_2(\BR^+)^\prime$. 
 
If $L_1$ and 
$L_2$ have the same zeros in the open upper half plane, we assert that 
${\cal M}_1(\BR^\pm)={\cal M}_2(\BR^\pm)$, and hence also 
${\cal M}_1(I^\prime)={\cal M}_2(I^\prime)$ for bounded intervals 
$I$. This may be seen as follows. 
Suppose $L_i(p)=R_i(p)P(p)$, where $R_i$ has only real zeros, $i=1,2$, 
while the zeros of $P(p)$ have
strictly positive imaginary parts. If $f$ is a test function with support 
in $\BR^\pm$ and 
$\varepsilon>0$ we define $g_\varepsilon$ by  
$\tilde{g}_\varepsilon(p)=R_1(p)\tilde{f}(p)/R_2(p\pm i\varepsilon)$. Since 
$\tilde{g}_\varepsilon$ has no poles in the upper (lower) half plane, 
$g_\varepsilon$ has again support in $\BR^\pm$. Since $L_2(p)\tilde 
g_\varepsilon(p)$ obviously converges to $L_1(p)f(p)$ in the one particle 
space of $\Phi_0$, it follows that 
$W_2(g_\varepsilon)=W_0(L_2(D)g_\varepsilon)$ converges weakly to 
$W_1(f)=W_0(L_1(D)f)$ as $\varepsilon\to 0$. Hence 
${\cal M}_2(I^\prime)\subset{\cal M}_1(I^\prime)$. Interchanging the role 
of 1 and 2 one then obtains
${\cal M}_1(\BR^\pm)={\cal M}_2(\BR^\pm)$. 
\bigskip
\vfill\eject
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
\noindent{\bbf 4. Violation of Duality and Essential Duality}
\bigskip
It is well known that the chiral $U(1)$-current $\Phi_0$ satisfies 
duality, i.e.,
$${\cal M}_0(I)^\prime={\cal M}_0(I^\prime)\eqno(4.1)$$
for all bounded intervals $I$. 
This follows from the analysis in [HL], see also [BSch]. If the 
polynomial $L$ is nonconstant with only real zeros, then 
${\cal M}(I)\neq {\cal M}_0(I)$  
and ${\cal M}(I^\prime)={\cal M}_0(I^\prime)$, by the results 
above. Thus duality 
is violated for 
such fields. They still satisfy wedge duality, however, 
because ${\cal M}_0$ does, and ${\cal M}(\BR^\pm)={\cal M}_0(\BR^\pm)$. 
Note also that the conformally covariant fields (2.9) can be extended 
to the compactified 
light ray, and duality holds for this extension by the general analysis 
in [BSch] (see also [BGL] and [GF]).

To complete the picture we shall now show directly (i.e., without using the 
duality properties of ${\cal M}_0(\cdot)$) that duality is always violated 
for the fields (2.8) with a nonconstant $L(p)$, and that essential duality 
is violated if $L(p)$ has zeros with a nonvanishing imaginary part. 

Let us consider duality first. Let $I\subset\BR$ be a bounded interval. If 
$L(p)$ and hence $Q(p)$ is not a constant, we can obviously find a test 
function $g$ such that $DQ(D^2)g(x)=0$ for $x\in I$, while $DL(D)g(x)\neq 
0$ for all $x$ in some open subinterval of $I$. The first property 
implies that $W(g)\in {\cal 
M}(I)^\prime$ because of (2.2). 
On the other hand, by the latter property of $g$ 
one can find a test function $h$ with support in $I$ such that 
$$\int \tilde{h}(-p)p L(p)\tilde{g}(p)dp= \int h(x)DL(D)g(x) dx\neq 
0.\eqno(4.2)$$ 
Let $f$ be the tempered distribution whose Fourier transform 
is $\tilde{f}(p)=\lim_{\varepsilon\to 
0^+}\tilde{h}(p)/L(p+i\varepsilon)$. Since $\int \vert p\vert 
\vert L(p)\tilde{f}(p)\vert^2 dp<\infty$, $W(f)$ and $K(f,g)$ are well 
defined. By (2.16), (2.4) and (4.2) we have 
$$K(f,g)=\int p L(-p)\tilde{f}(-p)L(p)\tilde{g}(p) dp=
\int \tilde{h}(-p)p L(p)\tilde{g}(p)dp\neq 0.\eqno(4.3)$$ 
Hence $W(f)$ and $W(g)$ do not commute. Since $W(g)\in {\cal 
M}(I)^\prime$, it is enough to check that $W(f)\in {\cal 
M}(I^\prime)^\prime$ in order verify our assertion that duality is violated.
But if $u(x)$ is a test function with support in $I^\prime$, then
$$K(f,u)=\int pL(p)L(-p)\tilde{f}(-p)\tilde u(p)dp=\int 
pL(p)\tilde{h}(-p)\tilde u(p)dp=K(-DL(-D)h,u)=0\eqno(4.4)$$
because $DL(-D)h$ has support in $I$. Hence $W(f)\in {\cal 
M}(I^\prime)^\prime$, so duality does not hold.

To check for essential duality let $h$ be a nonzero test function with 
support in a bounded interval $I$ and define $f$ in the same way as 
above, i.e., $\tilde{f}(p)=\lim_{\varepsilon\to 
0^+}\tilde{h}(p)/L(p+i\varepsilon)$. As before, $W(f)\in {\cal 
M}(I^\prime)^\prime$, and hence also $W(f_a)\in {\cal 
M}(I_a^\prime)^\prime$, where $f_a$ is defined by
$f_a(x)=f(x-a)$ and $I_a=I+a$. Define $g$ by $\tilde{g}(p)=
\lim_{\varepsilon\to 0^+}\tilde{h}(p)/L(-p-i\varepsilon)$. Since
$DL(D)h$ has support in $I$, a computation analogous to (4.4) shows 
that $W(g)\in {\cal 
M}(I^\prime)^\prime$.
Since $I_a\cap I=\emptyset$ for large 
enough $\vert a\vert$, essential duality implies that the function
$F(a)=K(f_a,g)$ vanishes for large enough $\vert a\vert$. 
Hence the Fourier 
transform of  $F$ must in that case be entire 
analytic. From (2.16), (2.6) and (2.7) it follows that this 
Fourier transform is given by
$$\tilde{F}(p)=\frac{pL(p)L(-p)\tilde{h}(p)\tilde{h}(-p)}{L(p)^2}=
(-1)^n\frac{P(-p)}{P(p)}\tilde{h}(p)\tilde{h}(-p).\eqno(4.5)$$
If $P(p)$ is not constant, then $P(p)$ has zeros in the upper half plane 
while the zeros of $P(-p)$ lie in the lower half plane. 
The function $\tilde{F}$ is then not entire analytic and essential duality 
is violated. \bigskip

%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
\noindent{\bbf 5. Modular Structures of the Wedge Algebras}
\bigskip
We shall now compute the modular groups defined by the vacuum state for the 
wedge algebras ${\cal M}(\BR^+)$ and ${\cal M}(\BR^-)$. In order to compare 
the modular groups for different $\Phi$'s it is convenient to realize all 
fields on the same Hilbert space as above, namely the Hilbert space ${\cal 
H}_0$ of $\Phi_0$. This is the Fock space over the one particle space 
${\cal H}_{01}=L^2(\BR, \theta(p)pdp)$. As before we write $L(p)=R(p)P(p)$, 
where $R(p)$ has only real zeros, $P(p)$ has only zeros with a strictly 
positive imaginary part, $P(-p)=P(p)^*$, and 

$R(-p)=(-1)^n R(p)$ for 
real $p$. 
For each $\lambda>0$ we define 
two unitary operators, $U_+(\lambda)$ and $U_-(\lambda)$  by
$$\eqalignno{U_+(\lambda)\psi(p)&=\lambda\frac{P( 
p)}{P(-p)}\frac{P(-\lambda 
p)}{P(\lambda p)}\psi(\lambda p)&(5.1)\cr
U_-(\lambda)\psi(p)&=\lambda\frac{P(- 
p)}{P( p)}\frac{P(\lambda 
p)}{P(-\lambda p)}\psi(\lambda p)&(5.2)\cr}$$
for $\psi\in{\cal H}_{01}$ and canonical extension to the Fock space 
${\cal H}_0$. That $U_\pm(\lambda)$ is unitary follows from the reality 
condition $P(-p)=P(p)^*$ for $p\in\BR$, which means that ${P(\lambda 
p)}/{P(-\lambda p)}$ is just a phase factors for real $p$. It is clear that 
$U_\pm(\cdot)$ is a representation of the multiplicative group $\BR^+$. 
Moroever, $U_+=U_-$ if and only if $P(p)$ is a constant, in which case 
$U_\pm(\lambda^{-1})$
is the representation $U_0(\lambda)$ of the Lorentz boosts for 
$\Phi_0$, cf.\ (2.10).

If $\psi$ is of the form $\psi(p)=L(p)\varphi(p)$, then 
$U_+(\lambda)\psi(p)=L(p)V_+(\lambda)\varphi(p)$ with
$$V_+(\lambda)\varphi(p)=\lambda{L(-\lambda p)\over L(-p)}\varphi(\lambda 
p).\eqno(5.3)$$
Here we have used that $R(p)/R(-p)=\pm 1$ for real $p$. In the same way
$U_-(\lambda)\psi(p)=L(p)V_-(\lambda)\varphi(p)$ with
$$V_-(\lambda)\varphi(p)=\lambda{L(\lambda p)\over L(p)}\varphi(\lambda 
p).\eqno(5.4)$$
$V_\pm$ is of course just the unitarily equivalent realization of 
$U_\pm$ in the Fock space constructed over the one particle space of 
$\Phi$, {\it viz.\/} ${\cal H}_1=L^2(\theta(p)pQ(p^2)dp)$.

  
Since  ${L(\lambda 
p)}/{L(-\lambda p)}$ is analytic in $p$ in the upper half plane for 
$\lambda>0$ it is clear that 
if $\tilde f$ is the Fourier transform of a test function with support in 
the right wedge $\BR^+$, then the same holds for $V_+(\lambda)\tilde f$. 
The analogous statement for the left wedge $\BR^-$ and $V_-(\lambda)$ is 
also clear. 
It follows that one can define one paprameter groups 
$\sigma^\pm_t$ of automorphisms of ${\cal M}(\BR^\pm)$ (realized as 
algebras on ${\cal H}_0$) by
$$\sigma^+_t(W(f))=U_+(e^{-2\pi t})W(f)U_+(e^{2\pi t})\eqno(5.5)$$
for ${\rm supp\ } f\subset\BR^+$, and
$$\sigma^-_t(W(f))=U_-(e^{2\pi t})W(f)U_-(e^{-2\pi t})\eqno(5.6)$$ 
for ${\rm supp\ } f\subset\BR^-$.

In order to show that the groups defined by (5.5) and (5.6) are indeed the 
modular groups associated with the vacuum state on ${\cal M}(\BR^+)$ and 
${\cal M}(\BR^-)$ respectively, it is sufficient to verify the KMS 
condition. We discuss this for the algebra ${\cal M}(\BR^+)$, the other is 
treated in the same way. One must show that for test functions $f$, $g$ 
with support 
in $\BR^+$ the function $F(t):=\la \Omega, \sigma^+_t(W(f))W(g)\Omega\ra$ 
has an analytic 
continuation from the real axis into the half 
strip $\{t+is\mid 0<s<1\}$ with
$$\lim_{s\uparrow 1} F(is)=\la \Omega, 
W(g)W(f)\Omega\ra.\eqno(5.7)$$
>From the Weyl relation (2.15) and the equation $\la\Omega,
W(h)\Omega\ra=\exp(-\Vert\tilde h\Vert^2/2)$, with $\Vert \cdot\Vert$ as in 
(2.19), it follows that (5.7) is equivalent to a corresponding relation 
for the two point function, where we find it convenient to use the variable 
$\lambda=e^{2\pi t}$ instead of $t$: 
The function $G(\lambda):=\la\Omega,\Phi(f)U_+(\lambda)\Phi(g)\Omega\ra$ 
has an 
analytic continuation in $\lambda$ from the positive real axis up 
into the cut plane $\BC\backslash 
\BR^+$, and 
$$\lim_{\theta\uparrow 2\pi}G(e^{i\theta})=
\la\Omega,\Phi(g)\Phi(f)\Omega\ra.\eqno(5.8)$$
We shall now verify (5.8). Since $\Phi(f)=\Phi_0(L(D)f)$ we 
have by (5.3) for 
$\lambda>0$:
$$\eqalignno{G(\lambda)&=\la\Omega,\Phi(f)U_+(\lambda)\Phi(g)\Omega\ra
=\int_{0}^{\infty}\tilde 
f(-p)\lambda{L(-\lambda p)\over L(- p)}\tilde g(\lambda 
p)pQ(p^2)dp\cr&=\lambda\int_{0}^{\infty}\tilde 
f(-p)\tilde g(\lambda 
p)pL(p)L(-\lambda p)dp.&(5.9)\cr}$$
Since $g$ is a test function with support in $\BR^+$, 
$\tilde g(\lambda p)$ is analytic in 
$\lambda$ in the upper 
half plane and  rapidly decreasing in $p\in\BR^+$, together with 
$d\tilde g(\lambda p)/d\lambda$, for fixed $\lambda$. Hence we may 
continue $G$ analytically, obtaining
$$G(\lambda e^{i\pi})=-\lambda\int_{0}^{\infty}\tilde 
f(-p)\tilde g(-\lambda 
p)pL(p)L(\lambda p)dp.\eqno(5.10)$$ 
Now the integrand is analytic in the lower half plane in $p$ with rapid
decrease at infinity, so we may 
rotate the integration contour clockwise by $\pi$, obtaining
$$G(\lambda e^{i\pi})=-\lambda\int_{0}^{\infty}\tilde 
f(p)\tilde g(\lambda 
p)pL(-p)L(-\lambda p)dp.\eqno(5.11)$$  
Finally, we again continue analytically in $\lambda$ and obtain
$$\lim_{\theta\uparrow 2\pi}G(\lambda e^{i2\theta})=
\lambda\int_{0}^{\infty}\tilde 
f(p)\tilde g(-\lambda p)pL(-p)L(\lambda p)dp.\eqno(5.12)$$
For $\lambda=1$ the right side is just 
$$\int_{0}^{\infty}\tilde 
 g(-p)\tilde f(p)pQ(p^2)dp=
\la\Omega,\Phi(g)\Phi(f)\Omega\ra.\eqno(5.13)$$

Having identified $\sigma_t^\pm$ as the modular groups of ${\cal 
M}(\BR^\pm)$ we can now write the polar decomposition of the Tomita 
operators $S_\pm$ that map  $A\Omega$ into $A^*\Omega$ for $A\in{\cal 
M}(\BR^\pm)$: We have $S_\pm=J_\pm\Delta_\pm^{1/2}$ with 
$\Delta_\pm^{1/2}=U_\pm(e^{i\pi})$, in particular
$$\Delta_+^{1/2}\psi(p)=-{P(p)^2\over P(-p)^2} 
\psi(-p)\eqno(5.14)$$ 
for $\psi\in{\cal H}_{01}$ of the form $\psi(p)=L(p)\tilde f(p)$, where 
$f$ has support in $\BR^+$, so $\tilde f$ is analytic in the upper half 
plane, and 
$$J_+\psi(p)=-{P(p)^2\over P(-p)^2}{\psi(p)}^*\eqno(5.15)$$
for all $\psi\in{\cal H}_{01}$. This defines the operators on the one 
particle space; the extension to the whole Fock space is by sums of tensor 
products. The corresponding formulae for ${\cal 
M}(\BR^-)$ are   
$$\Delta_-^{1/2}\psi(p)=-{P(-p)^2\over P(p)^2}
\psi(-p)\eqno(5.16)$$
and
$$J_-\psi(p)=-{P(-p)^2\over P(p)^2} {\psi(p)}^*\eqno(5.17)$$
We see that $J_+=J_-$ if and only if $P(p)^2=P(-p)^2$, 
i.e, if and only if $P(p)$ is constant, because $P(p)$  and $P(-p)$ have 
their zeros in different half planes. This shows anew that ${\cal 
M}(\BR^+)^\prime={\cal M}(\BR^-)$ if and only if $L(p)$ has only real zeros.


Finally we remark that by (5.15) the algebras 
${\cal M}_1(\BR^+)$ and ${\cal M}_2(\BR^+)$
generated by two different fields $\Phi_1$ and $\Phi_2$ 
have the same $J$-operators if and only if the corresponding 
polynomials $P_1$, $P_2$ differ at most by a constant factor. 
Since $\Omega$ is separating for 
${\cal M}_1(\BR^+)
\vee{\cal M}_2(\BR^+)$ (the commutant contains ${\cal M}_0(\BR^-$)), 
Tomita's Theorem implies that the algebras ${\cal M}_1(\BR^+)$ and 
${\cal M}_2(\BR^+)$
are equal if and only if their  $J$-operators  are equal. Hence  
${\cal M}_1(\BR^+)={\cal M}_2(\BR^+)$ if and only if 
$P_1$, $P_2$ are proportional, as already noted in Section 3. 
\bigskip
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
\noindent{\bbf 6. Connection with the Two Dimensional CPT Theorem}
\bigskip
In [B] it is proved that any two dimensional local net with
translational covariance and spectrum condition can be embedded into a 
Poincar\'e covariant net that is CPT invariant and satisfies 
duality. As pointed out in [B], it is not to be expected in 
general that the extended net is unique, in fact the construction in [B]
gives rise to infinite families of such nets. If the 
original net satisfies wedge duality, all these nets coincide, but 
in general they will all be different. We shall now show that this is 
indeed the case for the field (2.8) if $L(p)$ has a root 
away from the real axis.

The construction of [B] applied to a net ${\cal M}(\cdot)$ 
on a light ray defines to begin with two local 
nets ${\cal N}_+(\cdot)$ and ${\cal N}_-(\cdot)$ as follows: If $I_{a,b}$ 
denotes the interval $]a,b[$ and $\BR^+_a=]a,\infty[$, $\BR^-_a=]-\infty, 
a[$, then one defines
$$\eqalignno{{\cal N}_+(I_{a,b})&={\cal M}(\BR^+_a)\cap{\cal 
M}(\BR^+_b)^\prime&(6.1)\cr
{\cal N}_-(I_{a,b})&={\cal M}(\BR^-_b)\cap{\cal 
M}(\BR^-_a)^\prime&(6.2)}$$
Both nets contain the original net ${\cal M}(\cdot)$ as a subnet 
and they are
Poincar\'e covariant with CPT symmetry. The Lorentz boosts for 
${\cal N}_\pm(\cdot)$ are given by the modular group of ${\cal 
M}_\pm(\BR^\pm)={\cal N}_\pm(\BR^\pm)$, and the CPT operator is the 
$J$-operator of ${\cal M}_\pm(\BR^\pm)$.

The nets ${\cal N}_\pm(\cdot)$ generated by the field (2.8) can be 
decribed explicitly in terms of the net ${\cal M}_0(\cdot)$ of
the $U(1)$-current $\Phi_0$. For this purpose we define two unitary 
operators $Y_\pm$ on the Fock space ${\cal H}_0$ by 
$$\eqalignno{Y_+\psi(p)&={P(p)\over P(-p)}\psi(p)&(6.2)\cr
Y_-\psi(p)&={P(-p)\over P(p)}\psi(p)&(6.3)\cr}$$
for $\psi\in{\cal H}_{01}$ and canonical extension to ${\cal H}_0$. We 
assert that
$${\cal N}_+(I)=Y_+{\cal M}_0(I)Y_+^{-1}\qquad\hbox{\rm and}\qquad
{\cal N}_-(I)=Y_-{\cal M}_0(I)Y_-^{-1}\eqno(6.4)$$
for all $I$. To show this for ${\cal N}_+(\cdot)$ (the other case is 
analogous) we note first that 
since ${\cal M}_0(\cdot)$ satisfies duality we have
${\cal M}_0(I_{a,b})={\cal M}_0(\BR^+_a)\cap{\cal 
M}_0(\BR^+_b)^\prime$. This implies the corresponding relation for
the net $Y_+{\cal M}_0(\cdot)Y_+^{-1}$. Moreover, 
we have ${\cal 
N}_+(\BR^+)=\CM(\BR^+)$ and hence also ${\cal 
N}_+(\BR_a)=\CM(\BR_a^+)$ for all $a$ by translational covariance. 
It therefore suffices to check that $Y_+{\cal M}_0(\BR^+)Y_+^{-1}={\cal 
M}_+(\BR^+)$. But this is an easy consequence of the fact that $Y_+$ 
establishes a one to one correspondence between test functions $\tilde 
f(p)$ that are 
analytic in the upper half plane and functions of the form $L(p)\tilde 
g(p)$ with $\tilde g(p)$ analytic in the upper half plane: Since 
$L(p)=R(p)P(p)$ with $R(-p)=\pm R(p)$, we have $Y_+\tilde f(p)=L(p)\tilde 
g(p)$ with $\tilde g(p)=\pm \tilde f(p)/L(-p)$. 

The fact that ${\cal N}_+(I)=Y_+{\cal M}_0(I)Y_+^{-1}$ is reflected 
in the corresponding relations for the Lorentz boosts and the CPT 
operators. The Lorentz boosts for $\CM_0(\cdot)$ are given by (2.10) and 
hence for ${\cal N}_+(\cdot)$ by
$$Y_+U_0(\lambda)Y_+^{-1}=U_+(\lambda)\eqno(6.5)$$
where $U_+(\lambda)$ is the modular group for ${\cal 
N}_+(\BR^+)=\CM(\BR^+)$, cf.\ (5.1). The CPT operator for $\CM_0(\cdot)$ 
is the $J$ operator for $\CM_0(\BR^\pm)$, given by
$$J_0\psi(p)=-\psi(p)^*\eqno(6.5)$$
for $\psi\in{\cal H}_{01}$, and the CPT operator for ${\cal N}_+(\cdot)$ is thus
$$Y_+J_0Y_+^{-1}=Y_+^2J_0=J_+,\eqno(6.6)$$
cf.\ (5.15). The corresponding operators for $\CN_-(\cdot)$ 
are given by (5.2) 
and (5.17). It is clear that the nets $\CN_+(\cdot)$ and $\CN_-(\cdot)$ 
are equal if and only if $\CM(\cdot)$ satisfies wedge duality, or 
equivalently, if and only if $J_+=J_-$. As noted above, this holds if 
and only if $P(p)$ is a constant, i.e. $L(p)$ has only real roots.

As discussed in [B] one may for each of the nets $\CN_\pm(\cdot)$ produce
an infinite family of local nets
$$\CN_\pm^k(I)=(J_-J_+)^k\CN_\pm(I)(J_-J_+)^{-k},\quad k\in\BZ.\eqno(6.7)$$
All these nets are again Poincar\'e covariant, satisfy CPT invariance and 
duality and extend the original net 
$\CM(\cdot)$. In the present case we have 
$$J_-J_+=Y_+^4=Y_-^{-4}\eqno(6.8)$$
and thus
$$\CN_\pm^k(I)=Y_+^{4k\pm 1}\CM_0(I)Y_+^{-(4k\pm 1)}\eqno(6.9)$$ 
because $\CN_\pm(I)=Y_\pm\CM(I)_0Y_\pm^{-1}$ and $Y_-=Y_+^{-1}$. The CPT 
operator for $\CN_\pm^k(I)$ is 
$$Y_+^{4k\pm 1}J_0Y_+^{-(4k\pm 1)}=Y_+^{2(4k\pm1)}J_0.\eqno(6.10)$$
It is clear that unless $P(p)$ is a constant these operators are all 
different, and the same is therefore true for
the nets $\CN_\pm^k(\cdot)$. 

The models considered above have the special 
feature that the nets $\CN_+(\cdot)$ and $\CN_-(\cdot)$ are unitarily 
equivalent to each other, although they are represented differently on the 
Hilbert space of the net $\CM(\cdot)$. In fact, since $\CN_\pm(I)=Y_\pm 
\CM_0(I)Y_\pm^{-1}$ and $Y_+=Y_-^{-1}$, we have $\CN_+(I)= 
Y_+^{2}\CN_-(I)Y_+^{-2}$. More generally, the unitary equivalence of 
$\CN_\pm(\cdot)$ holds for all nets such that $\CM(\BR^-)$ is unitarily 
equivalent to $\CM(\BR^+)^\prime$, provided the equivalence is implemented 
by an operator commuting with translations. It is not to be expected that
this holds in general. 

A last point worth mentioning is that the nets $\CN_\pm^k(\cdot)$ do not 
exhaust the list of extensions of $\CM(\cdot)$ satisfying duality in 
the examples considered. In fact, $\CM(\cdot)$ is a subnet of 
$\CM_0(\cdot)$, which is not equal to any of $\CN_\pm^k(\cdot)$ 
if $P(p)$ is not constant, although these nets are all unitarily equivalent to 
$\CM_0(\cdot)$.
\bigskip
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
\noindent{\bbf 7. Higher Dimensional Examples}
\bigskip
In this last section we consider fields in $n$-dimensional 
Minkowski space,  $n>2$. The most general two-point function consistent 
with positivity, translational covariance, spectrum condition and  locality
has in Fourier space the form
$${\cal W}_2(p)=\sum_{i=1}^N M_i(p)d\mu_i(p)\eqno(7.1)$$ 
where $d\mu_i$ is a positive Lorentz-invariant measure with support in 
the forward light cone and $M_i$ is a polynomial that is positive on the 
support of $d\mu_i$, $i=1,\dots,N$. Guided by the low-dimensional 
examples considered above we 
shall compute the modular groups 
of the wedge algebras for generalized free fields on $\BR^n$
in the special case that  
the sum in (7.1) contains only one term, i.e.,
$${\cal W}_2(p)=M(p)d\mu(p),\eqno(7.2)$$ 
and the polynomial $M$ allows a factorization,
$$M(p)=F(p)F(-p)\eqno(7.3)$$
where $F(p)$ is a function (in general not a polynomial) 
with certain analyticity properties to be 
specified below. 


To describe the properties of $F$ we use the light cone coordinates 
$x_\pm=x^0\pm x^1$ for $x=(x^0,\dots,x^{(n-1)})\in\BR^n$ and denote 
$(x^2,\dots,x^n)$ 
by $\hat x$. The Minkowski scalar product is
$$\la x,y\ra=\mfr 1/2 (x_+y_-+x_-y_+)-\hat x\cdot\hat y.\eqno(7.4)$$
The right wedge, $W_R$, is characterized by $x_+>0$, $x_-<0$; 
hence the Fourier transform,
$\tilde f(p)=\int \exp (-i\la p,x\ra) f(x) d^n x$ of a test 
function $f$ with support in $W_R$ has for fixed $\hat p\in\BR^{n-2}$ 
an analytic continuation in $p_+$ and $p_-$ into the half planes 
${\rm Im\, } p_+>0$,
${\rm Im\, } p_-<0$. The property required for $F$ is that $F(\pm p)$
is analytic and $F(-p)$ {\it without zeros} in this domain, with 
$F(-p)=F(p)^*$ for $p\in\BR^n$. There is no lack of polynomials 
$M$ allowing such a 
factorization; one example (suggested by H.J. Borchers) is 
$$M(p)=(p^1)^2+\cdots+(p^n)^2+m^2\eqno(7.5)$$
with
$$F(p)=\sqrt{\hat p\cdot \hat p+m^2}+ip^1=\sqrt{\hat p\cdot \hat 
p+m^2}+\mfr 
i/2(p_+-p_-).\eqno(7.6)$$
If $d\mu(p)=\theta(p^0)\delta(\la p,p\ra-m^2)$  we can 
replace the polynomial (7.5) by $(p^0)^2$, hence the corresponding 
generalized free field is nothing but the time derivative 
$(d/dx^0)\Phi_m(x)$, where $\Phi_m$ is the free field of mass $m$. 


In analogy with (5.3) we now define for $\lambda>0$ the unitary operators 
$V_R(\lambda)$ 
on the Fock space ${\cal H}$ over the one-particle space 
${\cal H}_1=L^2(\BR^n, M(p)d\mu(p))$ by
$$V_R(\lambda)\varphi(p)={F(-\lambda p_+,-\lambda^{-1}p_-,-\hat 
p)\over F(- p_+,- p_-,-\hat 
p)}\varphi(\lambda p_+,\lambda^{-1}p_-,\hat p)\eqno(7.7)$$
for $\varphi\in{\cal H}_1$ and canonical extension to ${\cal H}$.
By means of $V_R(\lambda)$ we then define a one parameter group of 
automorphisms of the von Neumann algebra $\CM(W_R)$ on 
${\cal H}$ generated by the Weyl 
operators $W(f)$ with ${\rm supp\, }f\subset W_R$:
$$\sigma^R_t(W(f))=V_R(e^{-2\pi t})W(f)V_R(e^{2\pi t}).\eqno(7.8)$$
Note that we are working on the Fock space constructed over 
$L^2(\BR^n, M(p)d\mu(p))$ 
and not $L^2(\BR^n,d\mu(p))$, hence we do not make use of the 
analogues of the operators $U_+$ defined in (5.1).


By essentially the same computation that verified (5.8) one 
shows that (7.8) satisfies the KMS condition and is therefore the modular 
group defined by the vacuum state on $\CM(W_R)$. The corresponding 
modular operator is given by
$$\Delta_R^{1/2}\varphi(p)={F(p_+,p_-,-\hat 
p)\over F( -p_+, -p_-,-\hat 
p)}\varphi(-p_+,-p_-,\hat p)\eqno(7.9)$$
where $\varphi$ is analytic in $p_+$ in the upper half plane and in 
$p_-$ in the lower half plane. The modular conjugation is 
$$J_R\varphi(p)={F(p_+,p_-,-\hat 
p)\over F( -p_+, -p_-,-\hat 
p)}\varphi(p_+,p_-,-\hat p)^*.\eqno(7.10)$$
Note that (7.9) and (7.10) are written for $\varphi$ in 
the space $L_2(M(p)d\mu(p),\BR^n)$ 
that depends on the field,
while  $\psi$ in (5.14) and (5.15) belongs to
one particle space $L_2(\theta(p)pdp,\BR)$
of the chiral $U(1)$-current. This is the reason why there is a square 
in the phase 
factor in (5.14)-(5.15), while (7.9)-(7.10) has only the 
first power of $F$.




For the left wedge 
$W_L=\{x\mid x_+<0, x_->0\}$ the corresponding operators are
$$V_L(\lambda)\varphi(p)={F(\lambda p_+,\lambda^{-1}p_-,\hat 
p)\over F( p_+, p_-,\hat 
p)}\varphi(\lambda p_+,\lambda^{-1}p_-,\hat p),\eqno(7.11)$$
$$\Delta_L^{1/2}\varphi(p)={F(-p_+,-p_-,\hat 
p)\over F( p_+, p_-,\hat 
p)}\varphi(-p_+,-p_-,\hat p)\eqno(7.12)$$
and
$$J_L\varphi(p)={F(-p_+,-p_-,\hat 
p)\over F( p_+, p_-,\hat 
p)}\varphi(p_+,p_-,-\hat p)^*.\eqno(7.13)$$
 
By comparing 
(7.10) and (7.13) we see that the field satisfies the wedge 
duality condition 
$\CM(W_R)^\prime=\CM(W_L)$ if and only if $F(p)=F(-p)$ on the support of 
$d\mu$. This condition is, e.g., violated in the example (7.6), and the
arguments of Sect.\ 4 are easily generalized to show that neither does 
essential duality hold in this case.

The example (7.6) demonstrates also that the 
modular group of $\CM(W_R)$ may 
act nonlocally in the $\hat x$-directions. In fact, 
let $f$ be a test function with compact support in $W_R$. Under the 
transformation (7.7) the Fourier transform $\tilde f$ is mapped into
$$\tilde f_\lambda(p)={\sqrt{\hat p\cdot \hat p+m^2}-\frac 
i2(\lambda p_+-\lambda^{-1} p_-)\over\sqrt{\hat p\cdot \hat p+m^2}-\frac 
i2(p_+-p_-)}\tilde f(\lambda p_+,\lambda^{-1} p_-, \hat p).\eqno(7.10)$$
This is no longer the Fourier transform of a function of compact support 
in the $\hat x$-directions, 
because it is not analytic in $\hat p$. From this lack of analyticity it 
is not difficult to deduce that 
$W(f_\lambda)$ does not belong to any wedge algebra generated by the 
field unless the wedge is a translate of $W_R$ or $W_L$,
but we refrain 
from presenting a formal proof of this. The 
operator $W(f_\lambda)$ 
is still localized in the $x^0,x^1$-directions in the sense that it is 
contained in $\CM(W_R+a)\cap\CM(W_R+b)^\prime$ for some $a,b\in W_R$, 
in accordance with the theorem of Borchers [B]. 

\bigskip\bigskip
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%

%%%%%%%  
\vskip 0.4cm\noindent
{\bf Acknowledgements\ } I am grateful to professors H.J. Borchers and D. 
Buchholz for discussions and to the
Heraeus-Stiftung for financial support during my stay in 
G\"ottingen in the 
summer 1993.
\vskip 0.6cm\noindent
{\bbf References}
%\babsatz
%\vskip 0.2cm
\def\ref{\par\vskip 10pt \noindent \hangafter=1
\hangindent 22.76pt}
\parskip 5pt
{\baselineskip=3ex\eightpoint\smallskip
\font\eightit=cmti8
\font\eightbf=cmbx8
\def\it{\eightit}
\def\bf{\eightbf}

%
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\end

