\magnification = 1200
\hfuzz=10pt
\hsize=4.8in
\vsize=7.3in
\baselineskip=18pt
\hoffset=0.35in
\voffset=0.1in
\parindent=0pt
\def\R{I\!\!R}
\def\C{I\!\!\!\!C}
\def\N{I\!\!N}
\def\Q{I\!\!\!\!Q}
\def\Z{I\!\!\!\!Z}
\def\ui{[0,1]}
\def\O{\Omega_{\geq}}
\def\o{\omega}
\def\t{\theta}
\def\S{\Sigma_{\geq}}
\def\SE{\Sigma}
\def\s{\sigma}
\def\sp{\sigma^{\prime}}
\def\A{\cal A}
\def\L{{\cal L}}
\def\E{{\cal E}}
\def\Ln{{\cal L}_n}
\def\df{f^{\prime}}
\def\ddf{f^{\prime \prime}}
\def\dphi{\phi^{\prime}}
\def\dg{g^{\prime}}
\def\B{{\cal B}}
\def\di{\displaystyle}
\def\DSP{\Lambda ({\cal L} )}
\def\DSPn{\Lambda ({\cal L}_n )}
\def\ESP{{\rm ess}({\cal L} )}
\def\RES{r_{\rm ess}({\cal L} )}
\def\v{{{\rm var }\,}}
\def\t{\theta}
\def\A{{\cal A}}
\def\Dn{\Delta_n}
\def\Gn{\Gamma_n}
\def\lip{{\rm L}}

\centerline{\bf TRANSFER OPERATOR FOR PIECEWISE AFFINE}
\centerline{\bf APPROXIMATIONS OF INTERVAL MAPS}  


\vglue 0.2cm
\vglue 1.0cm
\centerline{ Viviane Baladi }
\centerline{\it ETH Z\"urich, CH-8092 Z\"urich, Switzerland}
\centerline{\it (On leave from CNRS, UMR 128, ENS Lyon, France)} 
\vglue 0.2cm\centerline{ Stefano Isola}
\centerline{\it Dipartimento di Matematica, 
Universit\'a degli Studi di Bologna,}
\centerline{\it I-40127 Bologna, Italy}
\vglue 0.2cm\centerline{ Bernard Schmitt}
\centerline{\it Universit\'e de Bourgogne, 
Laboratoire de Topologie - URA 755,}
\centerline{\it F-21004 Dijon, France}
\vskip 0.5cm
\centerline{\bf August 1994}
\vskip 0.2cm
{\bf Abstract.}
We consider a natural approximation scheme
for piecewise expanding, piecewise $C^{1+\rm{Lipschitz}}$, mixing Markov 
interval maps $f$
by piecewise affine maps.
We prove that the densities of the absolutely continuous
invariant probability measures of the approximations converge
exponentially fast to the density of the absolutely continuous
invariant probability measure of $f$
in the uniform norm. To do this we compare
the relevant transfer operators of the approximations with
that of $f$, and use recently developed perturbation
techniques.  

\vfill
\eject 

{\bf 1. Introduction.}
\vskip 0.2cm
A transformation $f$ of $\ui$ is called Markov if there exist
disjoint open intervals
$I_1, \dots ,I_l$, the union of
whose closures is $\ui$, such that
$f$ restricted to each $I_j$ is monotone and continuous, and such that the closure of  each
$f(I_j)$ is  the closure of a union of intervals $I_k$. When this property holds, one may
study  the dynamical system generated by the iteration of $f$ using symbolic
dynamics and transfer operators which are the same as those in equilibrium
statistical mechanics [Ru]. 
However the
statistical properties of the dynamical orbits 
of $f$ can only be fully described in
terms of Markov chains if the restriction of the
Markov map $f$ to each interval  $I_j$ is
affine. Indeed, in this case,  the associated transfer operator (see below)
has a finite matrix representation. Thus, given a (non-linear) Markov transformation $f$,
which we will assume to
be topologically mixing,
we are faced with the problem of approximating 
it with a sequence of piecewise affine Markov maps. 

 
We show that the above problem can be 
solved constructively. More precisely, we obtain 
a sequence of finite Markov stochastic matrices 
whose normalised eigenvectors to the eigenvalue one approach the 
stationary probability density
of $f$ exponentially fast in the uniform norm.
Our main technical tool is 
a non-standard perturbative argument, first used in [Ba.Yo] to 
deal with stochastic perturbations.


The problem
of finding the invariant probability
measure by discretisation of the transfer operator 
was first raised by Ulam [U] and has been studied
by many authors.
In particular, Gora and Boyarski  [Go.Bo]  considered
more general  approximation schemes than ours,
and did not need any Markov assumption. 
However, they only obtained
the $L^1$ convergence  of the invariant
densities, and
no estimate on the speed of this convergence
(we believe that the methods from [Ba.Yo] used 
in the present article would yield another proof of
the $L^1$ convergence of the
invariant densities obtained by [Go.Bo, p. 865] for piecewise affine,
Markov approximations of topologically
mixing piecewise monotone interval maps which
are not necessarily Markov).
See  [Li], [Ke1, p.328] for other approximation
schemes, also with results in an $L^1$
framework, and [Sc] for some numerical 
results.

This work was made possible by a visit of the first two named authors
to the Universit\'e de Bourgogne and we are grateful for the warm
hospitality enjoyed in the Laboratoire de Topologie.




\vskip 1cm
{\bf 2. Markov transformations of $\ui$ and their piecewise affine
approximations.} 
\vskip 0.2cm
Our assumption on the transformation $f:\ui \to \ui$ is that 
there exist points $0=a_0 <a_1 < 
\ldots < a_{\ell} =1$ such that

\item {1)} for each $i=1,\dots ,\ell $, 
the restriction $f_i=f_{|_{\di \, ]a_{i-1},a_{i}[}}$ is
monotone, $C^1$ and $C^1$-extends to $[a_{i-1},a_{i}]$,
with a Lipschitz derivative $\df_i$;
this extension coincides with $f$ at least at one of the endpoints
$a_{i-1}$ or $a_i$;
\vskip 0.1cm
\item{2)} there is a number $\rho > 1$ such that 
$|\df_i|\geq \rho, \;\; i=1,\dots ,\ell$;
\vskip 0.1cm

\item{3)} for any $1\leq i,j \leq \ell$, if $f(]a_{i-1},a_{i}[)\, \cap \,
]a_{j-1},a_{j}[ \, \not= \emptyset$, then 
$f(]a_{i-1},a_{i}[)\supset ]a_{j-1},a_{j}[$;
\vskip 0.1cm
\item{4)} 
there exists $k_0 \ge 1$ such that $f^{k_0}$  
is onto on each branch of
monotonicity (this is equivalent to a topological mixing assumption).

\vskip 0.2cm
We set $|f'(a_i)| := \min \{ \lim_{y \uparrow a_i} |f'(y)|,
\lim_{y \downarrow a_i} |f'(y)| \}$ (with the obvious modification for
$a_0, a_\ell$).

It is well known that under the above conditions there is a
unique absolutely continuous invariant probability measure 
(a.c.i.p.m.) whose density $h$ is the unique normalised positive eigenfunction
with eigenvalue one of a transfer operator $\L$
defined on measurable functions $\phi $ by
$$
\L \phi(x) = \sum_{f(y)=x} {\phi (y)\over |\df (y)|} \, .
$$


Several interesting properties of the dynamical 
system generated by
$f$ are intimately related to
$\s(\L)$, the spectrum of $\L$ (see e.g. [Co]). However, the
latter depends crucially on the Banach space
considered. If one is interested in 
the unique a.c.i.p.m.,  one can let
$\L$  act on the ``large'' function space 
$L^1({\rm Lebesgue})$. Then, the spectral radius of $\L$
is equal to $1$, which is the only
element of the spectrum of $\L$ on the unit circle
and is a simple eigenvalue
with a positive normalised eigenfunction $h$
mentioned above, 
finally {\it each} $z\in \C$ with $|z|< 1$  is an eigenvalue of $\L$
with infinite multiplicity
([Ke.2]). 

Recall that given a Banach space
of functions on the interval
$(\B ,\Vert \;\, \Vert )$ such that our transfer
operator $\L : \B \to \B$
is bounded, we may define
the essential spectral radius, $\RES(\B)$, by:
$$
\eqalign
{
\RES(\B) = \inf \{ &r \in \C \; : \; z \in \sigma(\L:\B
\to \B) \, ,
|z| > r \, \Rightarrow \cr
&z {\rm \,\,\, is \,\,\, an \,\,\, isolated \,\,\, eigenvalue 
\,\,\, of \,\,\, finite \,\,\, multiplicity } \}\, .
}
$$
We define the discrete spectrum
of $\L$ acting on $\B$ to be the set of points $z$ in $\sigma(\L)$
with $|z| > \RES(\B)$.
If $h \in \B$, $\RES(\B) < 1$, and if $1$ is the only
eigenvalue of modulus $1$, then, setting 
$$
\tau := \max \{|\lambda |\;
:\; \lambda \in \sigma(\L)\setminus\{ 1\} \}< 1 \, ,
$$ 
for any  $\phi\in \B$ and any
$\epsilon >0$, the spectral decomposition of $\L$ yields that
$$
\Vert \L^k \phi - (\int \phi(x) dx )\cdot h \Vert \leq C (\tau +\epsilon)^k
\Vert \phi \Vert \, .\eqno(2.1)
$$
In other words, 
$\tau$ determines the rate of convergence to equilibrium, also called 
{\sl rate of mixing}. 


We shall consider $\L$ acting on the space
of function of bounded variation $(BV ,\Vert \;\, \Vert )$. Recall that the 
total variation of $\phi : \ui \to \R$ on an interval $[a,b]$ is 
$$
\v_{_{[a,b]}}\phi = \sup \{\sum_{i=0}^{n-1}|\phi(x_{i+1})-\phi(x_i)|\, : \,
n\geq 1, \, a\leq x_0 < \ldots < x_n \leq b \, \}\, .
$$
Let then $BV := \{\phi :\ui \to \R \; : \; {\v}_{_{\ui}} \phi< \infty \}$ and
$$
\Vert \phi \Vert = \Vert \phi \Vert_{\infty} + \v_{_{\ui}} \phi \, .\eqno(2.2)
$$
The spectrum of $\L$ in this setting has been studied 
by several authors ([Wo], [Ho.Ke], [Ry], [Ke2], [Ba.Ke]): 
the spectral
radius is equal to one, $\L$ has $1$ as an eigenvalue
(and no other eigenvalues on the unit circle), and its
essential spectral radius $\RES(BV)$ is 
$$
\t = \lim_{k\to \infty} \left(\, \sup (\, 1/|(f^k)^{\prime}|\,)\, \right)^{1/k}
\leq 1/\rho< 1 \, .\eqno(2.3)
$$
We now construct a sequence $\{f_n\}$ 
of piecewise affine approximations to $f$.
For any $n\geq 1$
let $\tilde \A_{n}$ be the (mod $0$) partition of $\ui$ whose elements are the 
intervals of the form
$
I_{i_0}\cap f^{-1}(I_{i_1})\cap \ldots \cap f^{-(n-1)}(I_{i_{n-1}})$,
where $I_j = ]a_{j-1}, a_j[$
(i.e., the iterate $f^{n}$ is monotone
on each $I \in \tilde \A_n$). Let $\A_n$ be the partition
(in the strict sense) of $[0,1]$ obtained by adding
one or two endpoints to atoms of $\tilde \A_n$, in such a
way that $f^k|I$ is continuous for each $I \in \A_k$
(there might be several ways of doing this).



{\bf Definition.} {\it The $n$-th piecewise affine approximation of $f$
is the transformation $f_n$ of $\ui$ such that for any $I\in \A_{n}$ the restriction 
${f_n}_{|I}$ is affine,
and for any extremal point $x$ of $I \in \A_n$}
$$
\lim_{y\uparrow x}f_n(y) = \lim_{y\uparrow x}f(y), \quad
\lim_{y\downarrow x}f_n(y) = \lim_{y\downarrow x}f(y)
$$
{\it Again, we set $|f'_n(x)| := \min \{ \lim_{y \uparrow x} |f_n'(y)|,
\lim_{y \downarrow x} |f_n'(y)| \}$ 
if $x$ is an endpoint of $I \in \A_n$, with the obvious modification for
$a_0, a_\ell$.}


The transfer operator associated to $f_n$ is 
$$
\Ln \phi(x) = \sum_{f_n(y)=x}{\phi (y)\over |f'_n(y)|} \, . \eqno(2.4)
$$
The results mentioned above apply,
in particular  $1$ is a simple eigenvalue of $\Ln$ acting on
$BV$, with normalised positive eigenfunction
$h_n$ equal to the density of the
unique a.c.i.p.m.,
and (2.3) yields a value $\t_n$ for the essential spectral radius.

\vskip 0.2cm
We now want to characterise the discrete spectrum and the
corresponding eigenfunctions of $\Ln: BV \to BV$. 
Let $\Dn$ be the closed $\Ln$-invariant subspace of $BV$ defined by
$$
\Dn = {\rm span} \, \{\, {\chi}_{I} \, : \, I\in \A_n\, \}\, .\eqno(2.5)
$$Then,
for any $n\geq 1$, we may
consider the restricted operator ${\Ln}_{|\Dn}$, and the coinduced 
operator ${\Ln}^{\Gn}$, acting on the quotient space $\Gn = BV/\Dn$. We have 
the 
decomposition [Er.La]
$\s(\Ln) \subseteq \s({\Ln}_{|\Dn}) \cup \s({\Ln}^{\Gn})$.
Moreover, it is
easy to check that  in the natural
basis for $\Dn$, the restriction ${\Ln}_{|\Dn}$ is given by  the
$\ell^n \times \ell^n$ matrix $M^{(n)}$ defined by:
$$
M_{ij}^{(n)} = {|J_j\cap f^{-1}_n(J_i)|\over |J_i|}
={ |J_j| \over
\sum_k |J_k \cap f(J_j)|} \, , \qquad J_i,J_j\in \A_{n}
$$
By the mixing assumption, the matrix $M^{(n)}$  is irreducible and aperiodic,
so that
$\sigma(M^{(n)})=\{1\}\cup \sigma_n$,
where $\sigma_n$ is strictly contained in the unit disc.
On the other hand, the norm induced by (2.2) on $\Gn$ is
$\Vert \phi \Vert^{\Gn} = \Vert \phi - Q_n\phi \Vert$,
where $Q_n:BV \to \Dn$ is given by
$$
Q_n\phi (x) = \sum_{I\in \A_n} \alpha_I(\phi)\, \chi_I(x), \qquad
\alpha_I(\phi) = {1\over |I|}\, \int_I \, \phi(s)\, ds\, ,
$$ 
so that the spectral radius of ${\Ln}^{\Gn} : BV \to BV$ is easily seen
to be $\leq \t_n$ and thus $=\t_n$
(see e.g. [Ba]). Putting together these observations
we have:
\vskip 0.2cm
{\bf Lemma 2.1.} 
$$
\{ z \in \s(\Ln) \, , |z| > \t_n \} = \{ z \in \s({\Ln}_{|\Dn})\, , |z| > \t_n \} =
\{ z \in \s(M^{(n)}) \, , |z| > \t_n \} \, .
$$
{\it In particular, the normalised
fixed function $h_n$ of $\Ln$ is in $\Dn$, and
is a fixed vector of the matrix $M^{(n)}$.}
\vskip 0.2cm
We are now in a position to state our main result.
\vskip 0.2cm
{\bf Theorem.} {\it Let  $f$ be a piecewise
monotone interval map satisfying assumptions (1)-(4) from
the beginning of this section, let $h$ be the density
of its unique a.c.i.p.m. and $\tau$ its rate
of mixing. Let $\L_n$ be the transfer
operators of the $n$-th piecewise affine approximation of $f$.

Then there is
a constant $C_1> 0$ and for each
$\kappa^2 > \tau$  a
constant  $C_2>0$ such that for each $n \ge 1$ the
normalised eigenfunction $h_n\in \Dn$ for the
simple eigenvalue $1$ of $\L_n$ satisfies
$$
\eqalign
{\v h_n &\le C_1 \cr
\sup_{x \in \ui} |h_n(x) - h(x)| &\le C_2 \kappa^{(2/3)n} \, .
}
$$
Moreover, the spectrum of $\L_n$ decomposes as $\{ 1\} \cup
\Sigma_n$ with rate of mixing
$\tau_n=\sup \{ z \in \Sigma_n\} < 1$
and if $\tau \ne r_\ESP$, the rates
$\tau_n$ converge to the rate
of mixing of $f$, i.e., $\lim_{n \to \infty}
\tau_n = \tau$.}
\vskip 0.2cm
{\bf Remark.}  
We only prove convergence of the maximal
eigenvector. This is related to the fact that
the nature of our approximations forces the use of balanced norms
(see below). It would 
be interesting 
to know whether a different approach would yield results
on eigenvectors corresponding to other elements of the discrete
spectrum. Note also that we do not
know whether the obtained exponential rate of convergence
($\tau^{1/3}$) is optimal.

\vskip 0.2cm
The proof of our theorem uses two lemmas. Lemma 2.2 is the analogue of
the ``dynamical'' Lemma 9 in [Ba.Yo] and Lemma 2.3 corresponds
to the ``abstract functional lemmas'' in [Ba.Yo]. 
The Markov situation considered here
yields a simplification and a strenghtening of the results,
because there are no ``bad'' intervals of monotonicity (in the
terminology of [Ba.Yo]).

We first make some preliminary remarks.
For each $\tilde \theta > \theta$,
there exists $k_1 \ge 1$ so that for all $n\ge k \ge k_1$ and
all $I \in \A_k$,
$$
\sup_{x \in \bar I} {1\over |(f_n^k)'(x)|}\le
\sup_{x \in \bar I} {1\over |(f^k)'(x)|}  \le \tilde \theta^k\, ,\eqno(2.6)
$$
and also (see [Ba.Ke, Lemma 2.3])
$$
\v_{\bar I} {1\over |(f_n^k)'(x)|} 
\le\v_{\bar I} {1\over |(f^k)'(x)|} \le \tilde \theta^k\, .\eqno(2.7)
$$
(We may assume that $k_1$ is a multiple
of $k_0$: this will be convenient below.)
Observe also
that for any $\tilde \t > \t$,
there exists a constant $C$
such that for all $k \ge 1$ the maximum length of the intervals
in $\A_k$ is not larger than 
$$
\sup_{I \in \A_k}
\sup_{x \in \bar I} {1\over |(f^k)'(x)|}  \le 
C \, \, \tilde \theta^k\, .
\eqno(2.8)
$$
It will be necessary to make use of balanced
norms in $BV$: for $0<\gamma \leq 1$ define
$$
\Vert \phi \Vert_{\gamma} = \Vert \phi \Vert_{\infty} + 
\gamma \, \v_{\ui} \phi \, .
$$

{\bf Lemma 2.2.} {\it Let ${\t} < \kappa^2 <1$. 
Then there exists 
$C_3 > 0$ such that for all
$n\ge (3/2) k\ge k \ge k_1$ }
$$
\Vert {\L}^k - {\Ln}^k \Vert_{\kappa^k} \leq C_3\kappa^{k}\, .
$$
\vskip 0.2cm

{\it Proof of Lemma 2.2.}
Fix ${\tilde {\t}}$  with
$\t< {\tilde {\t}} < \kappa^2$.

 
We start by preliminary computations useful to control the
supremum part of the norm. 
For $n\ge k \geq k_1$, 
we denote by $(\psi_I^k)_{I\in \A_{n}}$ and $(\psi_{n,I}^k)_{I\in \A_{n}}$
the collection of the inverse branches of all the restrictions to the 
atoms of $\A_{n}$ of $f^k$ and $f^k_n$ respectively.
Since $n \ge k$, we have for $\phi \in BV$:
$$
{\L}^k \phi (x)=\sum_{I\in \A_{n}} {\chi_{f^k(I)}(x)\, \phi (\psi_I^k(x)) 
\over |(f^k)^{\prime} (\psi_I^k(x))| },\qquad 
{\Ln}^k \phi (x)=\sum_{I\in \A_{n}} {\chi_{f^k(I)}(x)\, 
\phi (\psi_{n,I}^k(x)) 
\over | (f_n^k)^{\prime}(\psi_{n,I}^k(x))| }
$$
where the characteristic functions $\chi_{f^k(I)}=
\chi_{f^k_n(I)}$ are the same in both
sums by the definition of $f_n$. 
Therefore
$$
\eqalign{
|{\L}^k \phi (x) - &{\Ln}^k \phi (x) | \cr
&\leq 
\sum_{I\in \A_{n}}{|\phi (\psi_I^k(x)) -\phi (\psi_{n,I}^k(x)) |
\over |(f^k)^{\prime} (\psi_I^k(x))| }\, \chi_{f^k(I)}(x) \, + \cr
&+\, \sum_{I\in \A_{n}}|\phi (\psi_{n,I}^k(x))|\left|
{1\over (f^k)^{\prime} (\psi_I^k(x)) }-
{1\over  (f_n^k)^{\prime}(\psi_{n,I}^k(x)) }\right| \, \chi_{f^k(I)}(x) \,\cr
& = 
\, {\rm I} + {\rm II} \, .
\cr }\eqno(2.9)
$$
A straightforward calculation using (2.6) yields 
$$
{\rm I} \leq \,\, \v_{[0,1]} (\phi)   \, \, \tilde \theta^{k} \, . \eqno(2.10)
$$
The second term can be estimated as follows.
Let $K> 0$ be such that
${\L}^k1(x)\leq K$ for all $k \ge 1$
(such a constant $K$ exists  because
$\| \L^k 1 \|_\infty \le \int \L^k 1 \,  dx + \v_{[0,1]} \L^k 1
= \|\L^k 1\|$, and
(2.1) implies that $\|\L^k 1\|\le \| h \| + {\rm{cst}} (\tau +\epsilon)^k$)
and let $C>0$ be the constant
from (2.8). Then we will prove that
there is a constant $\bar C$ such that for all $n \ge k$:
$$
\eqalign
{
{\rm II}\,  &\leq  \| \phi\|_\infty 
\sup_{y_1,y_2 \in I\in \A_n}
\left| 
{ (f^k)^{\prime} (y_1)\over (f_n^k)^{\prime}(y_2)} -1
\right |
\sum_{I\in \A_{n}}
\left|
{1\over (f^k)^{\prime} (\psi_I^k(x)) } \right | \, \chi_{f^k(I)}(x) 
\cr
&\le \, \Vert \phi \Vert_{\infty}\, K   \, 
\bar C\,  C \tilde \t^{n-k}\,  . 
}\eqno(2.11)
$$
To obtain (2.11) we will use the following distorsion inequality:
if $f$ is piecewise $C^{1+\rm{Lipschitz}}$ and expanding
(in particular, $\log| f'|$ is piecewise Lipschitz), there
is a constant $\hat C>0$ so that  for each interval
$J$ of monotonicity of $f$ and all $x_1, x_2 \in J$,
$$
\left| 
{ f^{\prime} (x_1)\over f^{\prime}(x_2)} -1
\right | \le
\hat C \, |x_1 - x_2| \, .
$$
To apply this inequality, we first observe that
for all $n\ge k\ge 1$,
and all $y_1, y_2 \in I\in \A_n$, the mean value theorem (and the remark that
$f^m(I)= f^m_n(I)$ for all $0 \le m \le k$), yields 
$$
\eqalign{
{ (f^k)^{\prime} (y_1)\over (f^k_n)^{\prime}(y_2)} 
&= \prod_{m=0}^{k-1}
{ f'(f^m(y_1)) \over f_n'(f^m_n(y_2))} 
= \prod_{m=0}^{k-1}
{ f'(f^m(y_1)) \over f'(f^m_n(y_{2,m}))} \cr
}
$$
where each $y_{2,m}$ is in $I$.
We now combine the distorsion inequality with
a second application of the mean value theorem 
and obtain points $z_m=z_m(y_2) \in I$, and a constant $\bar C>0$ with
$$
\eqalign{0\le 
{ (f^k)^{\prime} (y_1)\over (f^k_n)^{\prime}(y_2)} 
&\le \prod_{m=0}^{k-1}
(1+\hat C | f^m(y_1) - f^m(z_m) |)\cr
&\le \prod_{m=0}^{k-1}
(1+\hat C\, \rho^{m-k}\,  | f^k(y_1) - f^k(z_m) |)\cr
&\le \exp \sum_{\ell=1}^{k}
\log (1+\hat C\, \rho^{-\ell}\,  | f^k(y_1) - f^k(z_{k-\ell}) |)\cr
&\le
\sup_{y_3 \in I} (1 + \bar C \, |f^k(y_1) - f^k(y_3)| )\, .
}
$$
Since
$f^k(y_1) $ and $f^k(y_3)$ are in the same atom
of $\A_{n-k}$   we may apply (2.8). It then suffices to
exchange numerator and denominator to get the other inequality required
for (2.11).
(On distorsion inequalities,
see e.g. [dM.vS, I.2, V.2].) 

Therefore,  using $\tilde \t < \kappa^2$,
there is $D_1 > 0$ so that for all  $n \ge (3/2)k\ge k \ge k_1$
and  $\phi \in BV$
$$
|{\L}^k \phi (x) - {\Ln}^k \phi (x) | \leq 
\tilde \theta^{k} \v_{_{\ui}} \phi
+  \Vert \phi \Vert_{\infty}\,K  \,  
\bar C \, C \, \tilde \t^{n-k}  
\le D_1  \kappa^{k} \Vert \phi \Vert_{\kappa^k} \, . 
\eqno(2.12)
$$

To estimate the variation, we write
$$
\v_{_{\ui}}({\L}^k \phi - {\Ln}^k \phi ) \leq 
\v_{_{\ui}}{\Ln}^k \phi + \v_{_{\ui}}{\L}^k \phi
$$
and bound each term of the right-hand-side separately.
We consider first $\Ln^k$ for 
$k= k_1$ where $k_1$ is a multiple
of $k_0$. We may assume that 
$2 \tilde \theta^{k_1} < \kappa^{k_1}$
(otherwise take $k_1$ to be a larger
multiple of $k_0$). Using  the fact that 
for each $I \in \A_{k_1}$ the branch
$f^{k_1}_{|_I}$ can be extended to a surjective
function on the closure of $I$
(and the inverse branches accordingly),
we find for each  $I\in {\A}_{k_1}$:
$$
\eqalign{
\v_{_{\ui}}{ \chi_{f^{k_1}(\bar I)}(x)\, \phi (\psi^{k_1}_{n,\bar I}(x)) 
\over | (f^{k_1}_n)^{\prime}(\psi^{k_1}_{n,\bar I}(x))| } &=
\v_{_{\ui}} {\phi (\psi^{k_1}_{n,\bar I}(x)) 
\over | (f^{k_1}_n)^{\prime}(\psi^{k_1}_{n,\bar I}(x))| }\cr
&\leq  \sup_{x \in \bar I} {1\over |({f_n}^{k_1})'(x)|}\, 
\v_{\bar I}\phi + \sup_{\bar I} |\phi |\,  
\v_{\bar I}{1\over  |(f^{k_1}_n)^{\prime}|}\cr
&\leq \tilde \theta^{k_1}\, 
\v_{\bar I}\phi +  \tilde \t^{k_1}\sup_{\bar I} |\phi |\cr
&\le 
2 \tilde \theta^{k_1}
\v_{\bar I}\phi +  \tilde \t^{k_1}\inf_{\bar I} |\phi |\, \cr
&\le 
\kappa^{k_1}\, 
\v_{\bar I}\phi +  \tilde \t^{k_1} \beta(k_1)^{-1}
\int_{\bar I} |\phi (x)| \, dx \, , \cr
}
$$
where $\beta(k_1)> 0$ is the minimum length of the  atoms of ${\A}_{k_1}$.
Hence taking the sum over the atoms of ${\A}_{k_1}$ 
we find
$$
\v_{_{\ui}}{\Ln}^{k_1} \phi \leq \kappa^{k_1}\, {\rm var}_{_{\ui}}\phi + 
\tilde \t^{k_1}\, \beta({k_1})^{-1}\, \int_0^1 |\phi(x) |\, dx\, .
$$
Finally, applying recursively the above inequality 
(and using  $\int|\Ln \phi|\, dx=
\int |\phi|\, dx$) we find a
constant $D_2 > 0$ so that for all 
$n\ge  k =m \cdot k_1 + p 
\ge k_1$ ($p< k_1$):
$$
\v_{_{\ui}}{\Ln}^k \phi \leq
D_2 ( \kappa^{k}\, \v_{_{\ui}}\phi + 
\tilde\t^{k_1}\, \beta({k_1})^{-1} \, 
{1- \kappa^{k}\over 1- \kappa^{k_1}}\, \int |\phi (x)|\, dx )\, .
$$
The estimate for $\L^k$ is exactly the same:
$$
\v_{_{\ui}}{\L}^k \phi \leq 
D_2 ( \kappa^{k}\, \v_{_{\ui}}\phi + 
\tilde\t^{k_1} \beta({k_1})^{-1}  \, 
{1- \kappa^{k}\over 1- \kappa^{k_1}}\, \int |\phi(x)|\, dx )\, .
$$
Putting together these estimates and using
$\int |\phi|\, dx \le \|\phi\|_\infty$, we find a constant
$D_3 > 0$ such that for all $n \ge k \ge k_1$
$$
\v_{_{\ui}}({\L}^k \phi - {\Ln}^k \phi ) \leq  
D_3 {\kappa}^k \, \v_{_{\ui}}\phi + D_3 \,  \Vert \phi \Vert_{\infty}\, .
\eqno(2.13)
$$
>From (2.12) and (2.13) and using
again $\tilde \t < \kappa^2$, we  obtain $C_3>0$ so that
for all $n \ge (3/2) k \ge k \ge k_1$
$$
\Vert {\L}^k - {\Ln}^k \Vert_{\kappa^k} \leq C_3\kappa^{k} \, . 
\, \, {\rm{Q.E.D.}}
$$
\vskip 0.2cm

 

We decompose the spectrum of
$\L$ on $BV$ into $\sigma(\L)=\Sigma_0 \cup \Sigma_1$ where
$\Sigma_0=\{ 1\}$, with the corresponding
decomposition into generalised eigenspaces 
$BV=X_0\oplus X_1=\C h \oplus X_1$,
and projections $\pi_0 : BV \to X_0$, $\pi_1 : BV\to X_1$
(see e.g. [Ka]).

\vskip 0.2cm
{\bf Lemma 2.3.} 
{\it Consider the operators $\Ln$ acting on $BV$
and let $\theta < \kappa^2 < 1$. For 
any  $\kappa'$ so that
$\tau/\kappa' < \kappa < \kappa' < 1$, there exist $C_4>0$ and 
$k_2 \ge 1 $ so that for all  $n\ge (3/2) k\ge k\ge k_2$:}
\item{1)}
{\it The spectrum $\sigma(\Ln)$ decomposes into}
$$
\sigma(\Ln)= \Sigma_0^n \cup \Sigma_1^n
$$
{\it with }
$$
\sup \{ |z| \mid z \in \Sigma_1^n \} 
< \kappa'  < \inf \{ |z| \mid z \in \Sigma_0^n \}  \, .
$$
\item{2)}
{\it Let $\pi_0^n : X_0^n \oplus X_1^n \to X_0^n$ be the projection
associated with this spectral decomposition, then for each $\eta > \kappa/\kappa'$}
$$
\|\pi_0 -\pi_0^n\|_{\kappa^k} < C_4 \, \eta^k \, .
$$
{\it (In particular, $\Sigma_0^n=\{1\}$ and $1$ is a simple
eigenvalue of $\Ln$.)}
\vskip 0.2cm




{\it Proof of Lemma 2.3.}
(We essentially follow [Ba.Yo].)
\item{1)}
Let $\tau'$ and $\kappa_0'$ be such that
$$  
{\tau \over \kappa'}< {\tau' \over \kappa'} <\kappa  < \kappa' 
< \kappa'_0  < 1\, .
$$ 
Let $k_2\ge k_1$ be a fixed multiple of $k_0$, large enough for various purposes. In particular, we
require that for $k \ge k_2$
$$  
\phi \in X_{1} \Rightarrow
\| \L^k \phi \| \le (\tau')^k\| \phi \| \, . 
$$                                             
For $n \ge (3/2)k\ge k\ge k_2$ we will show that
$\lambda \notin \sigma(\Ln)$ for $\lambda$
with $\kappa' < |\lambda| < \kappa'_0$ by
proving that the resolvent $R(\Ln^k,\lambda^k)
=(\Ln^k-\lambda^k \, \rm{Id})^{-1}$
is a bounded operator
on $(BV, \| \cdot \|_{\kappa^k})$. 
If the resolvent exists, it can be written as:
$$
R(\Ln^k,\lambda^k)=
\sum_{m=0}^\infty \bigl ( R(\L^k, \lambda^k) (\Ln^k-\L^k) \bigr)^m
\cdot R(\L^k, \lambda^k) \, .\eqno{(2.14)}
$$ 
By Lemma 2.2, it is enough to
show that $\|R(\L^k, \lambda^k) \|_{\kappa^k} < (1/\kappa)^k$. 
Since $R(\L^k,\lambda^k) X_i = X_i$ for $i=0,1$, we have for
$\phi \in X$, $\|\phi \|_{\kappa^k} =1$
$$
\eqalign
{
\| R(\L^k, \lambda^k) \phi\|_{\kappa^k} &\le
\| R(\L^k,\lambda^k) \pi_0 \phi\|_{\kappa^k}
+
\| R(\L^k, \lambda^k)\pi_1 \phi \|_{\kappa_k} \cr
&\le
\| R(\L^k, \lambda^k)|_{X_0} \|_{\kappa^k}
\| \pi_0\|_{\kappa^k}
+  
\| R(\L^k, \lambda^k)|_{X_1} \|_{\kappa^k}
\| \pi_1\|_{\kappa^k}\, . \cr
}
$$  
Since
$\pi_0 \phi= h \, \int \phi(x) \, dx$,
there exists a constant $A_0>0$
with 
$$
\| \pi_0 \phi \|_\infty \le \| h\|_\infty
|\int \phi(x) \, dx|\le A_0 \|\phi\|_1 \le A_0 \| \phi\|_\infty \, .
$$
Therefore
$\|\pi_0\|_{\kappa^k}$ and  $\|\pi_1\|_{\kappa^k} \le
1 + \|\pi_0\|_{\kappa^k}$ are uniformly bounded
(because $\|\pi_0 \phi \|_{\kappa^k}\le\|\pi_0\phi\|\le
A'\|\pi_0 \phi\|_\infty\le A' A_0 \|\phi\|_\infty 
\le A' A_0 \|\phi\|_{\kappa^k}$,
where we have used that all norms on $X_0$ are equivalent).
It thus suffices to bound
$\|R(\L^k, \lambda^k)|_{X_i} \|_{\kappa^k}$, $i=0,1$.


There exists a constant $A_1 > 0$ so that for all $\phi \in X_0$
$$
\| \L^k \phi -\lambda^k \phi \|_{\kappa^k}
\ge A_1 \cdot \| \phi \|_{\kappa^k} \, .
$$      
For $\phi \in X_{1}$, we have
$$
\| \L^k \phi \|_{\kappa^k}
\le \|\L^k \phi\| \le  (\tau')^k \| \phi\| \le
({\tau'\over \kappa})^{k} \| \phi \|_{\kappa^k} \, ,
$$
from which it follows that there is a constant $A_2 > 0$ with
$$  
\| \L^k \phi -\lambda^k \phi \|_{\kappa^k}
\ge A_2 \cdot (\kappa')^k \| \phi \|_{\kappa^k} \, .
$$
Therefore, there is a constant $A_3>0$ so that for all large enough $k$
$$
\| R(\L^k, \lambda^k) \|_{\kappa^k}\le
{A_3\over (\kappa')^k}
\le {1\over \kappa^k} \, .  \eqno{(2.15)}  
$$
\item{2)}
Note that $\pi_0$ can be viewed as the projection associated
with $(\L^k, (\Sigma_0)^k)$ for any $k$, and similarly
for $\pi_0^n$. We will again
consider a fixed $k\ge k_2$ and $n \ge (3/2) k$.

We write $B_\delta$ for the circle of radius $\delta$ centered
at $0$ in $\C$.
Let $\kappa_0'$ be as in part (1) and
let $\gamma = B_{{\hat \kappa}^k} \cup B_{r_0^k}$ for some 
$\kappa' < \hat \kappa < \kappa_0'$, with
$\hat \kappa <\eta (\kappa')^2/\kappa$
(using $\eta(\kappa')^2/\kappa > \kappa'$) and
$r_0 > 1$.
Then by (1),
$\Sigma_0^k$ and $(\Sigma_0^n)^k$ are contained
in the annular region bounded by $\gamma$, and we have
$$
\pi_0 = {1 \over 2 i \pi}  \int_\gamma
R(\L^k,\lambda) \, d\lambda \qquad\qquad 
\pi_0^n = {1 \over 2 i \pi} \int_\gamma
R(\Ln^k,\lambda) \, d\lambda \, .
$$
Therefore
$$
\eqalign
{ 
\| \pi_0 - \pi_0^n\|_{\kappa^k} & \le
{1 \over 2 \pi}
\int_\gamma \| R(\L^k, \lambda) - R(\Ln^k, \lambda)\|_{\kappa^k}\, d\lambda\cr
&\le 
{1 \over 2 \pi} \cdot \ell(B_{{\hat \kappa}^k}) \,
\max_{\lambda \in B_{{\hat \kappa}^k}} 
\| R(\L^k, \lambda) - R(\Ln^k, \lambda)\|_{\kappa^k} \cr
&\quad + {\rm \quad the \quad corresponding \quad term\quad  for \quad}
B_{r_0^k} \cr
&= {\rm III} + {\rm IV} \, . \cr
}
$$       

Using (2.14) we have
$$
\| R(\L^k, \lambda) - R(\Ln^k, \lambda)\|_{\kappa^k}  \le
\sum_{m=1}^\infty  \| R(\L^k, \lambda)\|_{\kappa^k}^{m+1}
\cdot
\| \Ln^k - \L^k\|_{\kappa^k}^m \, .
$$
Since
$\ell(B_{{\hat\kappa}^k}) = 2 \pi {\hat\kappa}^k$,
and
$\| R(\L^k, \lambda) \| \le A_3/ (\kappa')^k$
for $\lambda \in B_{\hat \kappa^k}$ (by (2.15)), we obtain
$A_4 > 0$ such that
$$ 
{\rm III} \le
{\hat\kappa}^k \,
\sum_{m=1}^\infty 
\biggl ( {A_3 \over {\kappa'}^k} \biggr )^{m+1} 
(\kappa^k)^m 
\le
A_4 \, {\hat\kappa}^k \cdot {\kappa^k \over ({\kappa'}^k)^2}
\le A_4  \, \eta^k \, .
$$                            

For $\rm{IV}$, we use $\ell(B_{{r_0}^k}) = 2 \pi {r_0}^k$,
to get $A_5> 0$ so that
$$
{\rm IV} \le A_5 \, r_0^k \,
{\kappa^k \over r_0^{2k}} 
\le A_5 \, \eta^k \, .\,  
$$
The assertion in parenthesis follows from classical perturbation results,
see e.g. [Ka]. Q.E.D.

\vskip 0.2cm
{\it Proof of the  Theorem.}

Let $\tau/\kappa' < \kappa < \kappa'<1$.
First we show that for $n \ge (3/2) k\ge k\ge k_2$  the space $X_0^n$ 
from Lemma 2.3  is the graph of
some linear $S_n : X_0 \to X_1$: Let $\phi \in X_0^n$, since 
$$
\eqalign
{
\|\pi_1 \phi\|_{\kappa^k}&=\| \phi - \pi_0 \phi \|_{\kappa^k} \le \| \pi_0^n - \pi_0 \|_{\kappa^k} 
\| \phi\|_{\kappa^k}\, ,\cr
\|\pi_0 \phi \|_{\kappa^k} &\ge \|\phi\|_{\kappa^k} (1 - \|\pi_0 -\pi_0^n\|_{\kappa^k})
\, , \cr
}
$$
it follows from Lemma 2.3(2) that 
$\|\pi_1 \phi\|_{\kappa^k} \ll \| \pi_0 \phi \|_{\kappa^k}$. In particular
if $\phi$, $\phi' \in X_0^n$ and $\pi_0 \phi = \pi_0 \phi'$, then
$\pi_1 \phi =\pi_1 \phi'$ and thus
$\phi = \phi'$.

We now  estimate $\| S_n\|_{\kappa_k}$.
Since ${\rm dim}\, X_0 =1$, and
$\Sigma_0^n=\{1\}$,  there exists $\phi_0 =\phi_0(n,k) \in X_0$, 
$\| \phi_0\|_{\kappa^k}=1$, such that
$$
\| S_n \|_{\kappa^k} = \|S_n \phi_0 \|_{\kappa^k}
= \| \pi_1 (\phi_0, S_n \phi_0)\|_{\kappa^k}
=  \| \pi_1 \Ln^k(\phi_0, S_n \phi_0)\|_{\kappa^k}\, .
$$                                              
For $\kappa^2 > \tau'' > \tau$ and large enough
$k$, Lemma 2.2 thus yields
$$
\eqalign{
\| S_n \|_{\kappa^k} 
&= \| \pi_1 \bigl [ \Ln^k(\phi_0, S_n \phi_0)
-\L^k \phi_0 +\L^k S_n \phi_0 - \L^k S_n \phi_0 \bigr ] \|_{\kappa^k}\cr
&\le
\| \pi_1 \|_{\kappa^k}
\biggl ( \bigl ( (\tau''/\kappa)^k + C_3 \kappa^k \bigr ) \| S_n \|_{\kappa^k}
+ C_3 \kappa^k \biggr ) \, .\cr
}
$$
Therefore, there exist $k_3\ge k_2$ and
a constant $B>0$ so that
for all $n \ge (3/2) k \ge k \ge k_3$
$$
\| S_n \|_{\kappa^k}
\le B\,  \kappa^k \, . \eqno{(2.16)}
$$
In particular, writing $[y]$ for the
integer part of $y$, for all $n \ge (3/2)k_3$
$$
\| S_n \|_{\kappa^{[(2/3)n}]}
\le B\,  \kappa^{[(2/3)n]} \, . \eqno{(2.17)}
$$

We need a bound on $\|S_n\|_\infty$. For
$n \ge (3/2)k_3$ and
$\phi \in X_0$ we have, using the
constant $A'$ from the proof of Lemma 2.3(1), 
$$
\eqalign
{ 
\|S_n \phi\|_\infty &\le \| S_n \|_{\kappa^{[(2/3)n]}} 
\| \phi \|_{\kappa^{[(2/3)n]}}\cr
&\le \| S_n\|_{\kappa^{[(2/3)n]}} 
(\kappa^{[(2/3)n]} \cdot A' \cdot \|\phi\|_\infty
+ (1-\kappa^{[(2/3)n]})\cdot \|\phi\|_\infty ) \cr
&\le (A'+1) B \kappa^{[(2/3)n]} \|\phi\|_\infty
\, . \cr
}
\eqno{(2.18)}
$$ 

By definition 
$$
h_n={ h+S_n(h) \over \int (h(x)+S_n(h)(x))\, dx}\ .
$$
Now
$
|\int (h(x) +S_n (h)(x)) \, dx - 1 | \le \|S_n(h)\|_\infty$,
which tends to zero as $n \to \infty$ by (2.18).
Therefore (2.17) implies that  for $n\ge (3/2) k_3$:
$$
\eqalign
{
\v h_n &\le
{\v h + \v S_n h \over
\int (h+S_n h) \, dx}\cr
&\le {\v h + \kappa^{-[(2/3)n]} \| S_n \|_{\kappa^{[(2/3)n]}} \| h\|
\over  1- \|S_n (h)\|_\infty }\cr
&\le (1+B) \|h\| (1+2 \|S_n (h)\|_\infty) \, ,
}
$$
which proves the existence of $C_1$.
We now bound $\|h_n -h \|_\infty$ using again (2.18):
$$
\eqalign
{\|h_n -h\|_\infty &\le{ (1+\|h\|_\infty) \|S_n h\|_\infty\over
1-\|S_n h\|_\infty}\cr
&\le (1+\|h\|_\infty) (1+2\|S_n h\|_\infty) (A'+1) B \kappa^{[(2/3)n]}
\|h\|_\infty  \, ,
}
$$
which proves the existence of $C_2$.

The statement on the convergence
of $\tau_n$  follows from the property of the convergence
of the discrete  spectrum in [Ba, Corollary to the main Theorem].
Q.E.D.


\vskip 0.8cm
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\end
