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intermittency, renewal sequences, return times, mixing rate
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\centerline{\bf RENEWAL SEQUENCES AND INTERMITTENCY}
\vglue 0.2cm
\vglue 0.2cm\centerline{Stefano Isola}
\vglue 0.4cm
\centerline{\it Dipartimento di Matematica, Universit\`a degli Studi di Bologna,}

\centerline{\it piazza di Porta S.Donato 5, I-40127 Bologna, Italy.}
\centerline{\it e-mail: isola@dm.unibo.it}
\vskip 1cm
\vskip 1cm {\bf Abstract.}
In this paper we examine the generating function $\Phi (z)$ of 
a renewal sequence arising from
the distribution of return times in the `turbulent' region
for a class of 
piecewise affine interval maps introduced by Gaspard and Wang$^{(1)}$ 
and studied by several authors$^{(2-8)}$. 
We prove that it admits a meromorphic
continuation to the entire complex $z$-plane with a branch cut along the ray
$(1,+\infty )$. Moreover we compute the asymptotic behaviour of the coefficients
of its Taylor expansion at $z=0$. From this, the exact polynomial
asympotics for the rate of mixing when the 
invariant measure is finite and of
the scaling rate when it is infinite are obtained.

\vfill \eject
{\bf  0. INTRODUCTION.}
\vskip 0.1cm
\noindent
The Pomeau-Manneville$^{(9)}$ type 1 intermittency model (at the tangent bifurcation
point) consists of a class of smooth
transformations $f:\ui \to \ui$ which are expanding everywhere but at
a neutral fixed point at the origin. Such {\sl intermittent interval maps}
provide with no doubt the simplest examples of `chaotic'
dynamical systems with anomalous statistical behaviour. 
For instance they may possess but a $\sigma$-finite non-normalizable invariant
measure$^{(10-12)}$. Or else, they may leave invariant a
probability measure with slow (e.g. polynomial) speed of mixing$^{(14-16)}$. 
Finally, in the framework of thermodynamic formalism,
they may exhibit phase transitions$^{(6-8)}$
and dynamical $\zeta$-functions with non-polar singularities$^{(14,18)}$.

\noindent
Here we consider a one parameter family of linearized 
intermittent interval maps (see eq.(1.2) below) introduced by 
Gaspard and Wang$^{(1,2)}$. 
As far as its statistical properties are concerned, it
is equivalent to a Markov chain with countable state space$^{(13)}$.
It is also related to the statistical mechanics model introduced by Fisher$^{(17)}$ 
and successively studied by Gallavotti$^{(18)}$ (see also Hofbauer$^{(19)}$).
Without pretending to be a typical example, 
the main advantage of this approximation scheme is that it
partially allows for exact calculations. 

The main concern of this paper is
the study of the 
generating function $\Phi (z)$ of a renewal sequence arising from
the distribution of return times in 
a region where the map is uniformly expanding.
This function coincides, up to a factor $(1-z)^{-1}$, 
with the Ruelle dynamical $\zeta$-function$^{(30)}$, 
and is shown to admit a meromorphic continuation
to the the entire complex $z$-plane with a branch cut along the ray
$(1,+\infty )$.
It appears that finding analytic 
continuation of dynamically defined functions, 
which are holomorphic in a domain given {\sl a priori}, can be a rewarding
mathematical achievement in itself.
Moreover, it will be shown that the main statistical 
features of this dynamical system
such as the rate of mixing or the scaling rate, are 
embodied in the behaviour of its Taylor coefficients. 

\vskip 0.5cm
\noindent
{\bf  1. PRELIMINARIES.}
\vskip 0.1cm
\noindent
Let $q,r,s$ be three real parameters satisfying $0<q<1$, $s>0$ and $r+1=q^{-s}$.
Let moreover $d_n$, $n\geq 0$, be defined by 
$$ 
d_0=1, \;\;
d_n= (1+nr)^{-1/ s},\;\;\; n\geq 1. \eqno(1.1)
$$ 
In particular $d_1=q$.
The numbers $d_n$ form
a Kaluza sequence$^{(20)}$, i.e. they satisfy: 
$$
0<d_n \leq d_0=1,\qquad d_n^2\leq d_{n-1}d_{n+1},\eqno(1.2)
$$
which is equivalent to the assertion that $d_{n+1}-2\lambda d_n +\lambda^2 d_{n-1}\geq 0$
for all $\lambda >0$.
Moreover they generate a countable partition of
$\ui$ into the intervals $A_n=[d_{n},d_{n-1}]$, $n\geq 1$, and 
the length $\rho_n$ of the interval $A_n$ has the asymptotic behaviour 
$$
\rho_n=d_{n-1}-d_n= \,(r/s)\, (1+nr)^{-1-1/s} + 
{\cal O}( (1+nr)^{-2-1/s})\, .\eqno(1.3)
$$ 
Set 
$\alpha_n = {\rho_n/ \rho_{n-1}}$, $n\geq 1$ (with $A_0=\ui$).
One then readily verifies that $1\geq \alpha_n > \alpha_{n-1}$ and
$\lim \alpha_n =\sup \alpha_n =1$.
We shall consider the piecewise affine map $f:\ui \to \ui$ defined by
$$
f (x) =\cases{  (x-d_1)/ \alpha_1, &if $x\in A_1$ \cr
        d_{k-1} + (x-d_k)/ \alpha_k, &if $x\in A_k,\,\, k\geq 2$. \cr
}\eqno(1.4)
$$
This map has been introduced as as a simplified model
for an intermittent interval map whose behaviour when $x\to 0^+$ is given by
$$
f(x) = x+u\, x^{1+s}+ {\cal O}(x^{1+s+\epsilon})
$$
where $u=r/s$ and $\epsilon >0$. Observe that the fixed point 
at the origin is neutral: $f'(0)=1$, and $f'(x)$ 
is only H\"older continuous at $x=0$, 
with exponent $s$. 

\noindent
We finally notice that
$f(A_{n})=A_{n-1}$ for any $n\geq 1$,
so that $\{A_n\}$ is a Markov 
partition for the map $f$. 

\vskip 0.2cm
\noindent
{\bf A countable Markov chain.}
One can say more: 
the iteration process $x_n=f^n(x)$, with $f$ as above,
is actually isomorphic (mod 0) to a Markov chain
with state space $\N$ and transition matrix $P=(p_{ij})$ given by
$$
P=\pmatrix{\rho_1&\rho_2&\rho_3&\ldots \cr
           1  &0  &0  &\ldots \cr
           0  &1  &0  &\ldots\cr
           0  &0  &1  &\ldots  \cr
           \vdots &\vdots &\vdots&\ddots \cr}\eqno(1.5)
$$
To see this, let $X$ be the residual set of points in $(0,1]$ which are not
preimages of $1$ with respect to the map $f$, namely
$X = (0,1] \setminus \{d_n\}_{n\geq 0}$. 
Let moreover $\O$ be the set of all one-sided sequences
$\o = (\o_0\o_1\dots )$, $\o_i\in \N$ s.t. given $\o_i$ then $\o_{i-1}=\o_i+1$ or $\o_{i-1}=1$. 
Then the map $\varphi:\O \rightarrow \ui$
defined by
$$
\varphi(\o) =x\quad\hbox{according to}\quad f^j(x)\in A_{\o_j},\;\; j\geq 0
$$  
is a bijection between $\O$ and $X$ and conjugates the map $f$ with the shift $T$ on $\O$.
It is then immediate to check that the stochastic process on
$\O$ given by  $x_i(\o)=\o_i$, $i\geq 0$, is a Markov chain with conditional
probabilities $p_{ij}=P(x_n(\o)=j\, |\, x_{n-1}(\o)=i)= m(f^{-1}(A_j)\bigcap A_i)/m(A_i)$, 
which coincide with those in (1.5).  
Since ${\rm g.c.d.}\{n: \rho_n>0\}=1$ the 
chain is aperiodic and recurrent. 
Consider the infinite sequence
$t_1,t_2,\dots$ of successive entrance times in the state $1$: 
$t_1=\inf\{i\geq 0\;:\; \o_i=1\}$ and, for $j\geq 2$, 
$t_j=\inf\{i>t_{j-1}\;:\; \o_i=1\}$. Let moreover
$r_j=t_{j+1}-t_j$ be the sequence of times between
returns.
The state $1$ being recurrent,
the numbers $r_j$ are i.i.d.r.v. under the probability $P_1(\cdot)=P(\;\cdot \;|x_0(\o)=1)$. 
Their common distribution
is $P_1(r_j=n)=\rho_n$ and their expectation value is given by 
$E_1(r_j)=\sum n\, \rho_n=\sum d_n$, which may be finite (positive-recurrent chain) or
infinite (null-recurrent chain) according whether $s<1$ or $s\geq 1$.
More specifically, we can define a family of moments 
$$
M^{(\ell)}=E_1(r_j^\ell)\equiv \sum n^\ell\, \rho_n,\qquad \ell \geq 0,\eqno(1.6)
$$ 
and say that the chain has {\sl ergodic degree} $\ell$ if $M^{(\ell)} <\infty$ but
$M^{(\ell +1)}=\infty$. Notice that $M^{(0)}=1$, so that the chain has
degree at least zero (null-recurrent case). 
Finally, the steady-state equation is $\pi_n=\sum_{i\in S}\pi_i\, p_{in}$
and is formally solved by $\pi_n=\pi_1\, d_{n-1}$, $n\geq 1$.
In the positive-recurrent case one finds
$\pi_1=(\sum d_n)^{-1}$. 
For more details on this Markov chain we refer to Isola$^{(13)}$. 

\vskip 0.2cm
\noindent
{\bf Invariant measure and return times.} We now return to our interval map $f$.
An easy consequence of the previous discussion is that it preserves an
absolutely continuous $\s$-finite measure $\nu$, 
whose density $e$ is given
by $$
e(x)=d_{n-1}/\rho_n,\qquad d_n<x\leq d_{n-1}.\eqno(1.7)
$$
It may be noted that
$$
\nu (A_{n})= d_{n-1} =\sum_{l\geq n}m(A_l),\eqno(1.8)
$$
where $m$ denotes the Lebesgue measure.
More specifically, if $E\subseteq A_n$, one readily sees that
$$
\nu (E) =\sum_{k\geq 0} m(A_{n+k}\cap f^{-k}E)=\sum_{k\geq 0}{m(E)\cdot m(A_{n+k})\over m(A_n)}
={m(E)\over m(A_n)}\, d_{n-1}.\eqno(1.9)
$$
Let $\tau : X \to \N$ be the {\it first passage time} in the interval $A_1$, that is
$$
\tau (x)= 1+ \min \{n\geq 0 \;:\; f^n(x)\in A_1\;\},\eqno(1.10)
$$ 
so that $A_n$ is the closure of the set $\{x\in X\, :Ê\, \tau (x)=n\}$. 
On the other hand, the {\it return time} function $r : X \to \N $ 
in the interval $A_1$ is given by
$$
r (x)=\min \{n\geq 1 \;: \; f^n(x)\in A_1\;\}=\tau \circ f(x).\eqno(1.11)
$$
Let $B_n=$ closure of $\{x\in A_1\, : \, r(x)=n\}$. Clearly 
$B_n= A_1\cap f^{-1}A_n\subset A_1$,
and therefore, using (1.9), we get
$$
\nu (B_n) = {m(A_1\cap f^{-1}A_n)\over m(A_1)}=m(A_n).\eqno(1.12)
$$ 
Putting togheter (1.8) and (1.12) we have the following chain of identities:
$$\eqalign{
\nu (\ui)&=\sum \nu (A_n)=\sum n\cdot m(A_n)=\int_0^1\tau(x)\, m(dx)\cr
&=\sum_n n\cdot \nu (B_n) 
=M^{(1)}=\int_{A_1}\, r(x)\, \nu (dx) ,\cr}
\eqno(1.13)
$$
which is a version of Kac's formula. Using the shorthand $M\equiv M^{(1)}$
we then have the following dichotomy: either $M < \infty$, and then there exists
an $f$-invariant a.c. probability measure $\mu = \nu/M$; or
$M = \infty$ so that $\nu$ is not normalizable and no invariant a.c. probability measure exists. 
In the latter case, the ergodic means
${1\over n}\sum_{k=0}^{n-1}\delta_{f^k(x)}$ converge weakly to the Dirac delta 
at $0^{(21,11)}$.

\noindent
For later use,
we now define recursively a family of formal `tail sequences' $d^{(\ell)}_n$,
with $\ell \geq 0$, derived from $d_n$ as follows: 
$$
d^{(0)}_n=d_n\quad\hbox{and}\quad d^{(\ell)}_n =\sum_{l>n}d^{(\ell-1)}_l
\quad\hbox{for}\quad \ell >0.
\eqno(1.14)
$$
Moreover we say that $a_n$ and $b_n$ are asymptotically equivalent
as $n$ approaches $\infty$, denoted as
$a_n \sim b_n\, $ $\; (n\to \infty)$,
if the quotient $a_n/b_n$ tends to unity. 
From (1.1) (see also (1.3)) we have that if $s < 1/\ell$, with $\ell\geq 1$, then the terms
$d^{(k)}_n$ are finite for $0\leq k\leq \ell$ and satisfy
$$
d^{(k)}_n \sim \, (1+(n+k)r)^{k-{1\over s}}.\eqno(1.15)
$$ 
It is also easy to check that 
$M^{(\ell)}$ is finite if and only if $d^{(\ell)}_n$ is.
Of special importance will be the asymptotic behaviour of $d^{(1)}_n$,
when $s<1$:
$$
d^{(1)}_{n-1}=\nu\left( x\in X \, :\, \tau(x)>n\right) \sim \, n^{1-{1\over s}}.\eqno(1.16)
$$
\noindent 
\vskip 0.5cm
{\bf  2. THE GENERATING FUNCTION OF THE RETURN TIMES DISTRIBUTION.}
\vskip 0.2cm
\noindent
If we view the element $A_n$ of the countable Markov partition introduced in Section 1 as the $n$-th `state' 
for our dynamical system, the number $\rho_n$ can be interpreted 
as the $m$-probability 
that a first passage in the state $1$ occurs after $n$ iterates.
Let us now consider the quantity 
$u_n:=m(f^{-(n-1)}A_1)$ which, for $n\geq 1$, gives the
$m$-probability to observe
a {\sl passage} in the state $1$ after $n-1$ iterates (for the first time or not).
We shall see in the next Section that $u_n$ is also equal to $\nu (A_1\cap f^{-n}A_1)$,
and can thus be interpreted as the
$\nu$-probability to observe a {\sl return} in the state $1$ after 
$n$ iterates. 
According to the discussion given in the previous Section,
the iteration process
$x_n=f^n(x)$ `starts afresh' at each passage in the state $1$, and
the sequence $u_0,u_1,\dots $ satisfies the recurrence relation
$$
u_0=1\quad\hbox{and}\quad u_n=\rho_n+u_1\, \rho_{n-1}\cdots + u_{n-1}\, \rho_1
\quad\hbox{for}\quad n\geq 1.\eqno(2.1)
$$ 
In other words, $u_0,u_1,\dots $ is the {\it renewal sequence}$^{(20)}$
associated with the sequence $\rho_1,\rho_2,\dots$. 
We now turn to the study of the
generating function $\Phi (z)$ of the sequence $u_n$, which is given by
the following formal power series
$$
\Phi (z) =\sum_{n=0}^{\infty} u_n z^n= \left(1-\sum_{n=1}^{\infty}\rho_n \, z^n\right)^{-1}=
\left( (1-z)\sum_{n=0}^{\infty}d_nz^n\right)^{-1}\cdot
\eqno(2.2)
$$
The next result can be viewed as a sharpening of a renewal 
theorem proved by Erd\"os, Feller and Pollard$^{(22)}$.
\vskip 0.1cm
{\bf Theorem 2.1 (Part one).} {\it The
power series defined in (2.2) defines a holomorphic function $\Phi (z)$
in the open unit disk and converges at every point of the unit
circle with the exception of $z=1$, where it has a non-polar singular point.
Moreover, one has
the following asymptotic behaviour 
of the coefficients $u_n$:
\item{a)} for $s<1$ we have
$u_n \sim ( 1+ n^{1-1/s})/M$;
\item{b)} for $s\geq 1$ we have}
$$
u_n \sim \cases{ n^{-1+1/s}, &if $s>1$ \cr
                1/\log n &if $s=1$. \cr }
$$
{\sl Proof.}  
We first notice that 
$$
0\leq {1\over \sum_{n=0}^{\infty}d_n}={1\over M } < 1.
$$
It is then easy to see that the function 
$D(z):=\sum_{n=0}^{\infty}d_nz^n$ has no
zeros for $|z|\leq 1$. Indeed, for $|z|<1$ this follows from (2.2), since
$\rho_n>0$ and therefore 
$|\sum_{n=1}^{\infty}\rho_n z^n| <1$ for $|z|<1$. Furthermore, 
from the above identity it follows that any zeros of $D(z)$ must be of the form
$e^{i\phi}$, $0<\phi < 2\pi$. Now, if $D(e^{i\phi})=0$
then (2.2) implies $\sum_{n=1}^{\infty}\rho_n\, e^{in\phi}=1$, that is
$\cos{(n\phi)}=1$, $\forall n \geq 1$, which is impossible.
Then the function $1/D(z)$ 
has no singularities in $|z|<1$ and
we can expand it in a power series $1/D(z)=\sum_{n=0}^{\infty}\gamma_n z^n$. 
Notice that $\gamma_0=1$. Set $h_n = -\gamma_n$ $(n\geq 1)$. 
We can then say more. 
By the property (1.2) of the sequence $d_n$,
we can apply Hardy$^{(23)}$, Theorem 22, and obtain 
$$
h_n \geq 0, \qquad \sum_{n=1}^{\infty}h_n \leq 1.\eqno(2.3)
$$ 
In addition, if $M = \infty$, then $\sum_{n=1}^{\infty}h_n = 1$.
In particular, it appears that ${1/ \sum_{n=0}^{\infty}d_n z^n}$ is absolutely
convergent for $|z| \leq 1$. 
This yields the announced analytic properties
of $\Phi (z)$ (the nature of the singularity at $z=1$ will be clarified
at the end of the proof). 

\noindent
To show statement (b), we start noticing that
$u_n = 1-h_1-\dots -h_n$ so that,
if $M =\infty$, the sequence
$a_n$ decreases monotonically to $0$.
Assertion (b) then follows from (1.14) and a 
repeated application of a Tauberian
theorem for power series (see, e.g., Feller$^{(24)}$, chap XIII.5, Theorem 5).

\noindent
Next, we are going to prove statement (a), for $s<1$. In this case, 
we have $u_n \to 1/M$ as $n\to \infty$.
To obtain more information we first note that
the relation
$$
\sum_{n=0}^{\infty}u_nz^n\, \cdot \,\sum_{n=0}^{\infty} d_nz^n = 
\sum_{n=0}^{\infty} z^n 
$$
implies
$$
\sum_{n=0}^{\infty}v_nz^n\, \cdot \,  \sum_{n=0}^{\infty} d_nz^n  = 
\sum_{n=0}^{\infty}d^{(1)}_n z^n \eqno(2.4)
$$
where $d^{(1)}_n$ is defined in (1.14) (see also (1.16)) and
$$ 
v_n := M \, u_n -1 \quad  (n\geq 0).\eqno(2.5)
$$
Moreover we have
$v_n=M\, \sum_{l>n}h_l$, so that the sequence $v_n$ is positive
and decreases monotonically to $0$.
 
\noindent
Put first $1/2 \leq s<1$. Then, according to (1.15), the term
$d^{(1)}_0$ is finite and 
the power series $\sum_{n=0}^{\infty}d^{(1)}_n z^n$
is divergent at $z=1$. 
Thus, for these values of $s$, a direct application of (1.15) and
the same Tauberian
theorem for power series used above give
$v_n \sim \, n^{1-1/s}$ and hence (a).
Furthermore, using again  
(1.15), we have that if
$1/(\ell+1) \leq s < 1/\ell$, with $\ell> 1$, then for $k\leq  \ell$ the terms
$d^{(k)}_0$ are finite and the power series 
$\sum_{n=0}^{\infty}d^{(\ell)}_n z^n$ is divergent at $z=1$.
On the other hand, it is easy to check that under these circumstances (2.4)
can be rewritten in the following way:
$$\eqalign{
\sum_{n=0}^{\infty}v_nz^n \, \cdot \,  \sum_{n=0}^{\infty} d_nz^n  \,= \,
(z&-1)^{\ell-1} \, \sum_{n=0}^{\infty}d^{(\ell)}_n z^n \, + \cr
&+ \, \sum_{k=2}^\ell(z-1)^{k-2}\left(d^{(k-1)}_0+d^{(k)}_0\right) \cr }
\eqno(2.6)
$$ 
so that the claimed result follows using the same reasoning as above,
along with the positivity and monotonicity of the sequences $d^{(\ell)}_n$.

\noindent
It remains to show that $z=1$ is a non-polar singularity for $\Phi (z)$.
Now, from (1.15) we have that if $s\geq 1$, then 
$(1-z)\Phi (z) \to 0$ even though $\Phi (z) \to \infty$ as $z\to 1_{-}$.
Moreover, if $1/(\ell+1) \leq s < 1/\ell$, then, denoting by $H_\ell (z)$
the expression in the r.h.s. of (2.6) and using again (1.15), we have
$(z-1)^{\ell} H_\ell(z) \to 0$ but $(z-1)^{\ell-1} H_\ell (z) \to \infty$ as $z\to 1_{-}$.
The assertion then follows for each of these functions, 
and in particular for $\Phi (z)$.
${\rm q.e.d.}$
\vskip 0.1cm
Let us now observe that
the coefficients $d_n$ can be considered as values of a function
$d(x)$ when $x$ ranges over the natural numbers. One may then examine the relation
between the analytic properties of the function $d(x)$ determining the coefficients 
and those of the function defined
by $D(z)=\sum_{n}d_nz^n$ (see for instance Dienes$^{(26)}$, p.335).
Along these lines we now prove the following theorem.
\vskip 0.2cm
\noindent
{\bf Theorem 2.1 (Part two).} {\it The function 
$\Phi (z)$ can be continued meromorphically to the entire
$z$-plane with a branch cut along the ray
$(1,+\infty )$. The meromorphic continuation is given by the formula, valid for any
$\delta > 0$,}
$$
\Phi (z) ={1\over (1-z)}\left( {1 \over 2\pi i}\int_1^{  +\infty}
\int_{{\rm Re}\, x =\delta}
d(x){t^{-x}\over t-z}dx dt \right)^{-1}
$$
where $d(x)= (1+rx)^{-1/ s}$.
\vskip 0.1cm
\noindent
{\it Proof.} 
The following proof relies on standard techniques of analytic continuation of
power series based on the use of the Mellin transform. The first step in this approach is the
construction of a function $d(x)$ defined on $\R_+$, which
reproduces the numbers $d_n$ at $x=n$ 
and extends to a function regular 
in the half-plane ${\rm Re}\, x > 0$. 
For our example this construction is effortless: $d(x)=(1+rx)^{-1/s}$.
Nevertheless we shall sketch below a procedure which may be
applied in more general situations, e.g. when the $d_n$'s are not explicitly known.
To this end, we first notice that if $\psi_0 (x)$ denotes the inverse branch of 
$f$ which maps $\ui$ onto
$[0,q]$, then we have $d_n=\psi_0^n(1)$. Let moreover $\psi:\ui \to [0,q]$ be 
a suitable smooth function
which interpolates $\psi_0$ at those points: $\psi (d_n)=d_{n+1}$, so that
$d_n=\psi^n(1)$ as well.
Now, a standard method for dealing with the asymptotic behaviour of iterated functions
starts considering the Abel equation (see, e.g., de Bruijn$^{(27)}$, p.160):
$G(\psi(x))=G(x)+1$.
If $G$ is known, up to an additive constant, and $\psi$ satisfies the above equation, 
one finds $\psi^n$ by
solving $G(\psi^n(x))=G(x)+n$
for $\psi^n(x)$. Suppose then to be able to determine a solution $G:[q,1]\to [0,1]$ 
of the Abel equation\footnote{$^{1}$}{The problem of the existence
of solutions of the Abel equation for a broad class of intermittent maps 
has been investigated by Prellberg$^{(6)}$.}, satisfying  
$G(1)=0$ and $G(q)=1$. Let $F(x) = G^{-1}(x): [0,1]\to [q,1]$.
A candidate for the function $d(x)$ is then obtained by extending $F(x)$ to $\R_+$ as
follows:
$$
d(x) = \psi^n\bigl( F(x-n)\bigr),\quad n\leq x \leq n+1,\quad n\geq 0.
$$
It is easy to check that
in our case the function 
$$
\psi(x) :=x(1+rx^s)^{-1/s}\eqno(2.7)
$$ 
satisfies the
above requirement\footnote{$^{2}$}{By the way, (2.7) is but the 
exact solution of the fixed point equation 
for the renormalization transformation with
intermittency boundary conditions$^{(28)}$.}
and a real analytic solution $G:[q,1]\to \ui$ of the Abel equation
(with $\psi$ as in (2.7))
which satisfies $G(1)=0$ and $G(q)=1$ is given by  $G(x)=(x^{-s}-1)/r$,
and its inverse is $F(x)=G^{-1}(x)=(1+rx)^{-1/s}$.
We therefore get $\psi^n(x)=F(G(x)+n)=x(1+nrx^s)^{-1/s}$ and $d(x)$ as announced above. 
Accordingly, the function $d(x)$ extends to a function regular 
in the half-plane ${\rm Re}\, x > 0$ and, for any $\delta >0$,
$$
d(x) \to 0, \quad d'(x) = {\cal O}(x^{-1-{1\over s}}), \quad x\to \infty, \quad
{\rm Re}\, x \geq \delta
$$
uniformly in ${\rm arg \,} x$.
We can then proceed as in Evgrafov$^{(29)}$, Section VII, Theorem 6.1. 
First, we take the Mellin transform of $d(-x)$,
$$
d(-x)=\int_1^{\infty} w(t) \, t^x \, {dt \over t}, \qquad 
w(t)={1 \over 2\pi i}\int_{{\rm Re}\, x =-\delta} d(-x)\, t^{-x}\, dx.
$$
In the first expression we put $x=-n$ and multiply by $z^n$.
Taking $|z|$ smaller than the distance from the origin to the contour
$(1,\infty)$, that is $|z|<1$, we sum over
$n\geq 0$ and, as we may interchange the order of summation and
integration, we get
$$
\sum_{n=0}^{\infty}d_n z^n = \int_1^{\infty}\sum_{n=0}^{\infty} 
{z^n\over t^{n+1}}\, w(t)\, dt
= \int_1^{\infty}{w(t)\over t-z}dt.
$$
The last integral converges uniformly in any closed region not containing points
of the ray $(1,\infty)$. We finish the proof by inserting the 
representation of $w(t)$ in the above integral ${\rm q.e.d.}$
\vskip 0.1cm
\noindent
{\bf Remarks.}
\vskip 0.1cm
\item{{\bf 1.}}
If one wishes,
one can investigate the behaviour of $\Phi (z)$ in a neighborhood of 
the branch point $z=1$ with the help of the above formula.
For example, taking $s=1$ one finds that $\Phi (z)$ has 
a logarithmic branch point at $z=1$.
\vskip 0.1cm
\noindent
\item{{\bf 2.}}
Consider the dynamical zeta function $\zeta (z)$ defined by 
the following formal series$^{(30)}$:
$$
\zeta (z) = \exp \sum_{n=1}^{\infty} {z^n\over n}Z_n,\qquad Z_n=
\sum_{x=f^n(x)} \prod_{k=0}^{n-1}{1\over |\df(f^k(x))|}.
$$
It is an easy task to realize that $Z_n=1+{\rm tr} (P_N)^n$ provided $N>n$,
where $P_N$ is the $N\times N$ truncation of the transition matrix (1.5) and
the $1$ comes from the neutral fixed point. A staightforward algebraic calculation
then gives
$$\eqalign{
{(1-z)/\zeta (z)} &=\lim_{N\to \infty}\exp -\sum_{n=1}^{\infty} {z^n\over n}{\rm tr} (P_N)^n \cr
&=\lim_{N\to \infty}\det (I-zP_N) =1-\sum_{n=1}^{\infty}\rho_n \, z^n\cr
}
$$
and therefore 
$$
\zeta (z) =(1-z)^{-1}\,\Phi (z). 
$$
The above identity and Theorem 2.1 (Part two)
answer a question raised by Dalqvist$^{(31)}$ for this particular model (see also 
Rugh$^{(32)}$ for related results
on Fredholm determinants).
\vskip 0.5cm
\noindent
{\bf 3. SCALING AND MIXING RATES.}
\vskip 0.5cm
\noindent
Given $U,V\in L^2(\ui, {\cal B} ,\nu)$ 
one may consider
the formal power series $S_{UV}(z)$ given by
$$
S_{UV}(z) := \sum_{n=0}^{\infty} z^n\nu (U\cdot V\circ f^n).
$$
Take first $U=V=\chi_{1}$, the indicator
function of the interval $A_1$. 
We have $\nu (\chi_1\cdot \chi_1\circ f^n)=\nu (A_1\cap f^{-n}A_1)=:u_n^{(1)}$,
which is the $\nu$-probability 
to observe a return in the state $1$ after 
$n$ iterates (recall that $\nu (A_1)=1$). 
Clearly, it satisfies the recurrence relation: 
$$
u^{(1)}_0=1\quad\hbox{and}\quad u^{(1)}_n=u^{(1)}_0\, \nu(B_n)+
\cdots + u^{(1)}_{n-1}\, \nu(B_1)
\quad\hbox{for}\quad n\geq 1,\eqno(3.1)
$$ 
where $B_n=\{x\in A_1\, : \, r(x)=n\}$ and $r(x)$ is defined in (1.11).
On the other hand we know that $\nu (B_n)=m (A_n)\equiv \rho_n$ and,
comparing with (2.1), we get $u^{(1)}_n\equiv u_n$, $\forall n$. We then have
the following
\vskip 0.1cm
\noindent
{\bf Proposition 3.1.}  $S_{\chi_{1}\chi_1}(z)=\Phi (z)$.
\vskip 0.1cm
\noindent 
Furthermore, if $M <\infty$, we can consider
the generating function of the correlation function of probability measure $\mu = \nu/M$
for the observable $\chi_{1}$. An easy calculation shows that
$$
\sum_{n=0}^{\infty} z^n\biggl( \, \mu (A_1\cap f^{-n}A_1) - (\mu(A_1))^2\, \biggr)
=(\mu(A_1))^2 \cdot \sum_{n=0}^{\infty} v_n z^n\eqno(3.2)
$$
where $\mu(A_1)=1/M$ and the $v_n$'s are defined in (2.5). Putting 
together Theorem 2.1 (Part one), Proposition (3.1) and equation (3.2) 
we obtain the following
\vskip 0.1cm
\noindent
{\bf Theorem 3.2.} {\it  
\item{a)} if $s<1$, then
$$
\mu (A_1\cap f^{-n}A_1) - (\mu(A_1))^2 \sim (\mu(A_1))^2 \,\, n^{1-{1\over s}};
$$
\item{b)} if $s\geq 1$, then 
$$
\lim_{ n\to \infty}\nu (A_1\cap f^{-n}A_1) =0
$$
but
$$
\lim_{ n\to \infty}{1\over u_n}\,\nu (A_1\cap f^{-n}A_1) = (\nu(A_1))^2 =1
$$ 
with $u_n$ given in (2.1).}
\vskip 0.1cm
\noindent
We now briefly dwell upon some consequences of the above result.
\vskip 0.2cm
\noindent
{\bf Mixing rate when the invariant measure is finite.}
Statement (a) of Theorem 3.2
can be generalized to a certain extent. Given $k\in \Z^+$, $k>1$, 
the analogous of relation (3.1) for $u^{(k)}_n:=\nu (A_k\cap f^{-n}A_k)$
reads $u^{(k)}_n=0$ for $n<k$, and
$$
{u^{(k)}_n\over \nu (A_k)} =u_0\, \rho_n+
\cdots + u_{l}\, \rho_{n-l},
\quad n=k+l, \quad l\geq 0.
$$ 
Therefore we have
$$
{1\over \nu (A_k)}\sum_{n=0}^{\infty} z^n\nu (A_k\cap f^{-n}A_k) =
\Phi (z) \cdot \sum_{n\geq k}z^n \, \rho_n\eqno(3.3)
$$
We now use the following result, whose proof can be found in 
Chung$^{(33)}$, Chap. I.5, Lemma A.
\vskip 0.2cm
\noindent
{\bf Lemma 3.3.} {\sl Let $\{s_n\}_{n\geq 0}$ be a 
sequence of nonnegative numbers not all vanishing.
If 
$$
\lim_{n\to \infty} {s_n\over \sum_{m=0}^ns_m}=0
$$
then, whenever the sequence $\{t_n\}_{n\geq 0}$ of real
numbers has a limit, we have}
$$
\lim_{n\to \infty}{\sum_{m=0}^{n}s_mt_{n-m}\over \sum_{m=0}^ns_m}
=\lim_{n\to \infty} t_n.
$$
\noindent
Using this result with $t_m=u_{m}$ and $s_m=\rho_{k+m}$ along with (3.3), 
we see that 
$$
\nu (A_k\cap f^{-n}A_k) \sim \nu (A_k) \cdot
\left(\sum_{m=0}^{n-k}\rho_{k+m}\right) \cdot u_{n-k}\sim 
(\nu (A_k))^2\cdot u_{n-k} \sim (\nu (A_k))^2\cdot u_{n}\eqno(3.4)
$$ 
where the last asymptotic equivalence holds for each fixed $k\in \Z^+$.
This gives
$$
\mu (A_k\cap f^{-n}A_k) - (\mu(A_k))^2 \sim (\mu(A_k))^2  
\,\, n^{1-{1\over s}}.\eqno(3.5)
$$
The same reasoning gives for a subset $E\subseteq A_k$, with $m (E) >0$,
$$
\nu (E\cap f^{-k-l}(E)) \sim \nu (E) \cdot
\left(\sum_{m=0}^{l}m(f^{-m}(E)\cap A_{k+m})\right) \cdot u_{l}\sim (\nu (E))^2
\cdot u_{l+k}
$$
where (1.9) has been used. We then get again
$$
\mu (E\cap f^{-n}E) - (\mu(E))^2 \sim (\mu(E))^2  
\,\, n^{1-{1\over s}}.\eqno(3.6)
$$
In an entirely analogous way one shows that (3.6) holds true
for $E\subseteq \cup_{l\in J}A_l$
where $J\subset \Z^+$ is any given finite set.

\noindent
Let ${\cal B}$ be the Borel $\s$-algebra on $\ui$
and consider the quadruple $(\ui, {\cal B}, \nu, f)$.
Clearly ${\cal A}$ generates ${\cal B}$.
Given $E\in {\cal B}$, we define the {\sl mixing rate} $\mu_n(E)$ of $E$ as
$$
\mu_n(E) := {\mu (E\cap f^{-n}E) - (\mu(E))^2\over (\mu(E))^2}\cdot\eqno(3.7)
$$
According to the above (see e.g. (3.4)) the mixing rate 
is not uniform in $E\in {\cal B}$.
To recover uniformity we define
$$
B_{+}:= \cup_{\epsilon} \{E\in {\cal B}: \, m (E)>0, 
\, E \subseteq \ui \setminus  (0, \epsilon)\,\},\eqno(3.8)
$$
where the union can be restricted to rational (positive) $\epsilon$ because
the set in the union increases as $\epsilon$ decreases.
An easy consequence of the above discussion is the following result
\vskip 0.1cm
\noindent
{\bf Lemma 3.4.} {\it  Let $E,F\in B_+$. Then $\mu_n(E) \sim \mu_n(F)$.}
\vskip 0.1cm
\noindent
Therefore, one can define the (self-) mixing rate $\mu_n(f)$ of the map $f$
as the rate of asymptotic decay of the sequences $\{\mu_n(E)\}$, with $E\in B_+$.
We summarize the above results in the following
\vskip 0.1cm
\noindent
{\bf Theorem 3.5.} {\it  If $M<\infty$ then
$\mu_n (f)= n^{1-{1\over s}}$.}
\vskip 0.1cm
\noindent
{\bf Remarks.}

\item{{\bf 1.}} We point out that Theorems 3.2 and 3.5 give 
the exact rate of mixing of the map $f$, not just a bound for it. 
In particular they improve all previously known bounds$^{(4,5)}$.
The above results
can be viewed as statements about the decay of correlations
for test functions as simple as indicators of sets in $B_+$. 
This makes the mixing rate (as defined above) determined by nothing but the
distribution of return times: $\nu\{x\in X \, :\, \tau(x)>n\}$ (compare (1.16)).
On the other hand, when dealing with correlation functions of
a broader class of observables, one expects a richer behaviour
depending also of the smoothness properties of the functions involved.
In particular one may obtain faster decays.
We refer to Isola$^{(14)}$, Liverani et al$^{(15)}$ and Young$^{(16)}$
for different approaches yielding more general results.

\item{{\bf 2.}} It turns out that the mixing rate is 
the same as above also for the set
$D_k=\cup_{l> k}A_l$ for some fixed $k\in \Z^+$. Indeed, we get
$$
{1 \over \nu ({D_k})}\sum_{n=0}^{\infty} z^n\nu (D_k\cap f^{-n}D_k)  = 
\Phi (z) \cdot \sum_{n\geq k}z^n \, d_n.
$$
Since $\nu ({D_k}) =\sum_{n\geq k}d_n$,
Lemma 3.3 gives
$$
\nu ({D_k}\cap f^{-n}D_k) \sim (\nu ({D_k})) \cdot \left(\sum_{m=0}^{n-k}d_{k+m}\right)
 \cdot u_{n-k} \sim (\nu ({D_k}))^2 \cdot u_{n},
$$
and therefore
$\mu ({D_k}\cap f^{-n}D_k) -(\mu({D_k}))^2 \sim (\mu({D_k}))^2  
\,\, n^{1-{1\over s}}$.
\vskip 0.2cm
\noindent
{\bf Scaling rate, wandering rate and return 
sequence when the invariant measure is infinite.} 
When $M=\infty$,
given $E\in {\cal B}$, with $\nu (E) >0$, 
we can define the {\sl scaling rate} $\sigma_n(E)$ of $E$ as
$$
\sigma_n(E) := {\nu (E\cap f^{-n}E)\over (\nu(E))^2}\cdot\eqno(3.9)
$$
From Theorem 3.2 we have that $\sigma_n(A_1) \sim u_n$. Moreover,
reasoning as above, one shows that $\sigma_n(E) \sim u_n$ for all $E\in B_+$.
We then define
the scaling rate $\sigma_n(f)$ of the map $f$
as the rate of asymptotic decay of the sequences $\{\sigma_n(E)\}$, $E\in B_+$.
By Theorem 2.1 (Part one) we obtain the following,
\vskip 0.1cm
\noindent
{\bf Theorem 3.6.} {\it  If $M=\infty$ then}
$$
\sigma_n (f)= \cases{  n^{-1+1/s}, &if $s>1$ \cr
                 1/\log n &if $s=1$. \cr }
$$
From the scaling rate, defined above, one can compute some other natural objects
arising in the ergodic theory of transformations preserving infinite
measures, notably the {\sl wandering rate} $w_n(f)$ and the {\sl return sequence} $r_n(f)$.
We refer to Thaler$^{(12)}$, Theorem 3, and also Aaronson$^{(10)}$, Theorem 3,
for precise definitions and a discussion of their relevant properties. Intuitively, 
$w_n(f)$ measures the
amount (measured with the measure $\nu$)
of $\ui$ visited by $f$-iterates of points of $B_+$ up to time $n$.
In our case it is simply given by the partial sums $\sum_{k=0}^nd_k$.
On the other hand, the existence of $r_n(f)$ is what makes the transformation 
$f$ {\sl weakly ergodic}$^{(11)}$, namely such that ${1\over r_n}\sum_{k=0}^{n-1}U(f^kx)$
converges in measure (but not $m$-almost surely) to $\nu(U)$ for any $U\in L^1(\ui, {\cal B} ,\nu)$.
These quantities can be readily obtained putting together Theorem 3.6 and the
asymptotic equivalences$^{(10)}$:
$$
w_n(f) \sim {n\over \sum_{k=0}^n\sigma_k},\qquad
r_n(f)\sim \sum_{k=0}^n\sigma_k.
$$
\vskip 0.1cm
\noindent
{\bf Concluding remarks.} We finally point out that using the above and 
results from Feller$^{(25)}$ one can obtain several limit theorems, 
at least for observables such as indicator functions of sets in $B_+$.
To give an example where Feller results are directly applicable, consider the test function $U=\chi_1$.
Then $N_n(x):=U(x)+\cdots +U(f^{n-1}(x))$
gives the number of passages in the state $1$ up to the $n$-th iterate of the map $f$.
Let moreover $g:X\to X$ be the induced map defined by $g(x)=f^{\tau(x)}(x)$. 
Then $S_n(x):=\tau (x)+\tau(g(x))\cdots 
+\tau(g^{n-1}(x))$ is the total number of iterates of $f$ needed to observe $n$ passages 
in the state $1$. 
Take first $s< 1/2$. Then, using the notation of Section 1, we have
$\sigma^2:=M^{(2)}-M^2<\infty$. This implies that the associated Markov chain
has ergodic degree at least two. One then shows$^{(25)}$ that the mean and the variance of the random 
variable $N_n$ are asymptotically equal to $n/M$ and  $\sigma/M^{3/2}$.
Moreover, observing that $m(x\in X :N_n(x)\geq k)=m(x\in X: S_k(x)\leq n)$, 
one obtain the following (central) limit theorem:
$$
m\left( x\in X \, :Ê\, N_n(x)\geq {n\over M}- {\sigma\sqrt {n}\over M^{3/2} }\, \alpha \right)
\to {1\over {2\pi}}\int_{-\infty}^{\alpha}e^{-y^2/2}dy.
$$
In the case $1/2\leq s <1$, in which the associated Markov chain
has ergodic degree one, as well as in the null recurrent case ($s\geq 1$),
one obtains different, non-normal, limiting distributions for which we refer
to Feller's paper.
\vskip 1cm
\noindent
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\vskip 0.2cm


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