Talk:Levy processes

The comment about Brownian motions who may jump is probably not good in this cntext; first, not every Lévy process has a Brownian part (you can comment that below in the Lévy-Khintchin decomposition), and second, from the point of view of non-local operators, having a Brownian part means that you have a Laplacian part in your non-local equation. Then the problem can be attacked with local techniques, which is exactly what we do not want to do.--Milton 11:59, 17 February 2012 (CST)

That sounds like a good point. I modified that sentence. I don't think Nestor will mind. (Luis 17:59, 17 February 2012 (CST))