The following theorems give us an easy way to determine if a
complicated function is continuous. We simply break the
function into simpler functions, and if our function is the
sum/difference/product/quotient/composition of continuous functions,
then it is continuous.
Theorem: If f(x) and g(x) are continuous at
x=a, and if c is a constant, then f(x)+g(x),
f(x)−g(x), cf(x), f(x)g(x), and f(x)g(x)
(if g(a)≠0) are continuous at x=a.
In short: the sum, difference, constant multiple,
product and quotient of continuous functions are
continuous.
(to understand why, see *
below)
Theorem:
If f(x) is continuous at x=b, and if
limx→ag(x)=b, then
limx→af(g(x))=f(b).
In short: the composition of continuous functions is
continuous.
(to understand why, see **
below)
Theorem: polynomial,
rational, root, trigonometric, inverse trigonometric,
exponential, and logarithmic functions are continuous
at every number in their domain.
Why do we care? By
definition, if f is continuous at x=a, then
limx→af(x)=f(a), which (if you think about it for a minute, and please DO)
means that to evaluate the limit of a
continuous function f as x→a, you need only plug in a
to f. It is easy to take the limit of a
continuous function!
The following video goes over these properties and
how to use them.
* This
theorem is a direct result of limit laws. For instance, to
see that f(x)+g(x) is continuous at x=a, we need to show
that limx→a(f(x)+g(x))=f(a)+g(a).
But limx→af(x)=f(a)(since f(x) is continuous),limx→ag(x)=g(a)(since g(x) is continuous),limx→a(f(x)+g(x))=limx→af(x)+limx→ag(x)(by our
limit laws), solimx→a(f(x)+g(x))=f(a)+g(a),
as required. Deriving the other properties is similar.
** To
see this, suppose that x is close to (but not equal) to a.
Then g(x) is close to b, since limx→ag(x)=b. Let y=g(x). Since f is continuous at b,
whenever y is close to b, f(y) is close to f(b). But
that makes f(g(x)) close to f(b).