M408M Learning Module Pages
Main page
Chapter 10: Parametric Equations
and Polar Coordinates
Chapter 12: Vectors and the Geometry of Space
Chapter 13: Vector Functions
Chapter 14: Partial Derivatives
Chapter 15: Multiple Integrals
Learning module LM 15.1:
Multiple integrals
Learning module LM 15.2:
Multiple integrals over rectangles:
Learning module LM 15.3:
Double integrals over general regions:
Learning module LM 15.4:
Double integrals in polar coordinates:
Learning module LM 15.5a:
Multiple integrals in physics:
Learning module LM 15.5b:
Integrals in probability and statistics:
Learning module LM 15.10:
Change of variables:
Change of variable in 1 dimension
Mappings in 2 dimensions
Jacobians
Examples
Cylindrical and spherical coordinates
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Cylindrical and spherical coordinates
Cylindrical and Spherical Coordinates
The change-of-variables formula with 3 (or more) variables is just
like the formula for two variables.
If we do a change-of-variables
Φ from coordinates (u,v,w) to coordinates (x,y,z), then the
Jacobian is the determinant
∂(x,y,z)∂(u,v,w) = |∂x∂u∂x∂v∂x∂w∂y∂u∂y∂v∂y∂w∂z∂u∂z∂v∂z∂w|,
and the volume element is
dV = dxdydz = |∂(x,y,z)∂(u,v,w)|dudvdw.
After rectangular (aka Cartesian) coordinates, the two most common an
useful coordinate systems in 3 dimensions are cylindrical coordinates
(sometimes called cylindrical polar coordinates) and spherical
coordinates (sometimes called spherical polar coordinates).
Cylindrical Coordinates: When there's symmetry about an
axis, it's convenient to take the z-axis as the axis of symmetry
and use polar coordinates (r,θ) in the xy-plane to measure
rotation around the z-axis. Check the interactive figure to the
right. A point P is specified by coordinates (r,θ,z)
where z is the height of P above the xy-plane.
(i) What happens to P as z changes?
(ii) What's the relation between r, P and the axis of symmetry?
(iii) What are the natural restrictions on θ?
(iv) The relation between Cartesian coordinates (x,y,z) and
Cylindrical coordinates (r,θ,z) for each point P in 3-space
is
x = rcosθ,y = rsinθ,z = z.
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Problem: Find the Jacobian of the transformation
(r,θ,z)→(x,y,z) of cylindrical coordinates.
Solution: This calculation is almost identical to finding the
Jacobian for polar coordinates. Our partial derivatives are:
∂x∂r=cos(θ),∂x∂θ=−rsin(θ),∂x∂z=0,∂y∂r=sin(θ),∂y∂θ=rcos(θ),∂y∂z=0,∂z∂r=0,∂z∂θ=0,∂z∂z=1.
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Our Jacobian is then the 3×3 determinant
∂(x,y,z)∂(r,θ,z) = |cos(θ)−rsin(θ)0sin(θ)rcos(θ)0001| = r,
and our volume element is dV=dxdydz=rdrdθdz.
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Spherical Coordinates: A sphere is symmetric in all directions
about its center, so it's convenient to take the center of the sphere
as the origin. Then we let ρ be the distance from the origin to
P and ϕ the angle this line from the origin to P makes with
the z-axis. Finally, as before, we use θ from polar
coordinates in the xy-plane to measure rotation around the
z-axis. Investigate the interactive figure to the right. A point P
is specified by 3 coordinates (ρ,θ,ϕ).
[Warning: Most physics texts swap the roles of θ and ϕ.]
(i) The relation between Cartesian coordinates
(x,y,z) and Spherical Polar coordinates (ρ,θ,ϕ) for each point P in 3-space is
x = ρcosθsinϕ,y = ρsinθsinϕ,z = ρcosϕ.
(ii) The natural restrictions on ρ,θ, and ϕ are 0≤ρ<∞,0≤θ<2π,0≤ϕ≤π.
(iii) Points on the earth are frequently specified by
Latitude and Longitude. How do these relate to θ
and ϕ?
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Problem: Find the Jacobian of the transformation
(ρ,θ,ϕ)→(x,y,z) of spherical coordinates.
Solution: Now our partial derivatives are:
∂x∂ρ=cos(θ)sin(ϕ),∂x∂θ=−ρsin(θ)sin(ϕ),∂x∂ϕ=ρcos(θ)cos(ϕ),∂y∂ρ=sin(θ)sin(ϕ),∂y∂θ=ρcos(θ)sin(ϕ),∂y∂ϕ=ρsin(θ)cos(ϕ),∂z∂ρ=cos(ϕ),∂z∂θ=0,∂z∂ϕ=−ρsin(ϕ).
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Our Jacobian ∂(x,y,z)∂(ρ,θ,ϕ)
is then the 3×3 determinant
|cos(θ)sin(ϕ)−ρsin(θ)sin(ϕ)ρcos(θ)cos(ϕ)sin(θ)sin(ϕ)ρcos(θ)sin(ϕ)ρsin(θ)cos(ϕ)cos(ϕ)0−ρsin(ϕ).|
which works out to ρ2sin(ϕ),
and our volume element is dV=dxdydz=ρ2sin(ϕ)dρdθdϕ.
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Problem: Compute the volume of the ball ρ≤R
or radius R.
Solution: If B is the unit ball, then its volume is
∭. We convert to spherical coordinates to get
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\begin{eqnarray*}
\hbox{Vol}(B) & = & \int_0^{\pi}\int_0^{2\pi} \int_0^R \rho^2 \sin(\phi)
d\rho d\theta d\phi \\
& = & \int_0^\pi \int_0^{2\pi} \frac{R^3\sin(\phi)}{3} d\theta d\phi \\
& = & \int_0^\pi \frac{2 \pi R^3 \sin(\phi)}{3} d\phi \\
& = & \frac{4 \pi R^3}{3}.
\end{eqnarray*}
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