Irreducible quadratic factors
are quadratic factors that when set equal to zero only have complex
roots. As a result they cannot be reduced into factors
containing only real numbers, hence the name irreducible. Examples include
x2+1 or indeed x2+a for any real number a>0, x2+x+1
(use the quadratic formula to see the roots), and 2x2−x+1.
When Q(x) has irreducible quadratic
factors, it affects our decomposition.
Irreducible quadratic factors of Q(x)
For every irreducible quadratic factor x2+bx+c of Q(x), we have
Ax+Bx2+bx+c
in the
decomposition.
For every repeated irreducible quadratic factor
(x2+bx+c)n of Q(x), we have the n terms
A1x+B1x2+bx+c+A2x+B2(x2+bx+c)2+…+Anx+Bn(x2+bx+c)n
in the decomposition.
Example: We have the decomposition 2x3+5x−1(x+1)3(x2+1)2=Ax+1+B(x+1)2+C(x+1)3+Dx+Ex2+1+Fx+G(x2+1)2.
Finding the coefficients A, B, etc. for these terms in the
decomposition can be challenging. We can't just plug in the
roots of Q(x) to get the coefficients one at a time, since the
quadratic factors don't have real roots. We either have to
plug in lots of different values of x, or compare the
corresponding coefficients of 1, x, x2, etc. Either way, we
get a system of linear equations to solve.
Finally, solving the integrals at the end is harder than with
linear factors, but we can do it:
To integrate ∫x(x2+a2)ndx, we
can substitute u=x2+a2.
To integrate ∫dx(x2+a2)n, where
u-substitution will not work, we can substitute
x=atan(θ).
These types of problems are explained in the following video.