Regular u-substitution works by setting u=g(x) for some function g. We have to pick u so that the integrand becomes a nice function of u times du. In the video, we explore inverse substitutions.
With inverse substitutions, we let x=g(θ), where typically g is a trig function. Then dx=g′(θ)dθ, and we can always rewrite the integrand in terms of θ and dθ. The tricky part is converting everything back to x at the end of the problem.
There are three very useful trig substitution:
For integrals involving x2+a2 or √x2+a2, use x=atan(θ).
Then dx=asec2(θ)dθ and x2+a2=a2sec2(θ). To convert back to x, draw a right triangle with opposite side x, adjacent side a and hypotenuse √x2+a2 and use soh-cah-toa.
For integrals involving a2−x2 or √a2−x2, use x=asin(θ).
Then dx=acos(θ)dθ and √a2−x2=acos(θ). To convert back to x, draw a right triangle with opposite side x, hypotenuse a and adjacent side √a2−x2 and use soh-cah-toa.
For integrals involving x2−a2 or √x2−a2, use x=asec(θ).
Then dx=asec(θ)tan(θ)dθ and √x2−a2=atan(θ). To convert back to x, draw a right triangle with adjacent side a, hypotenuse x and opposite side √x2−a2 and use soh-cah-toa.