Integration by Parts
After u-substitution, integration by parts is by far the most important technique to learn. It converts a hard integral ∫udv into an easier integral uv−∫vdu. The tricky thing is figuring out what to pick for u and dv. We want to choose u so that du is simpler than u, and dv so that v isn't much more complicated than dv. Remember that:
- Some functions get a lot simpler when differentiated or a lot more complicated when integrated. These almost always want to be part of u.
- Some functions get a little simpler when differentiated. These are a lower priority to include in u.
- Some functions, like ex and sin(x), don't get simpler at all. These have still lower priority, and usually are part of dv.
- Some functions actually get simpler when integrated and are almost always part of dv.
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If we can pick u from higher on the list and dv from lower on the list, then ∫vdu will be simpler than ∫udv.
If we have two terms at the same level, then we can try using some algebra to relate ∫vdu to ∫udv. We may have to integrate by parts twice to make this work.
Example:
Compute ∫ln(x)x3dx.
Solution:
Since
(ln(x))′=1x is simpler than ln(x) and ∫x−3dx is simpler than
x−3,
we take u=ln(x) and dv=1x3dx. Then
du=1x, and v=−12x2.
Hence
∫ln(x)x3dx=−ln(x)2x2−(∫−12x3dx)=−ln(x)2x2−14x2+C.
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